quentron.com

[profitis]

Sarkeizen:'Can you point me to where I was talking about an event?'

If two degrees of freedom of arrangement is 01 then how many degrees of freedom is represented by 0 1/2?

[profitis]

Here.you wrote this:O(X^1/2).what does this mean. You restricted quenco's ACTIONS to that.'The BBBV restricts the ability to create a machine
USING quantum effects which has a complexity class
of O(1) (for sorting EVENTS) because the BBBV states that the
greatest improvement you can get from quantum
EFFECTS is O(X^1/2).'

If 01 represents a sorting EVENT what kind of EVENT is O(X^1/2)

[sarkeizen]

Here.you wrote this:O(X^1/2).what does this mean

Uhm...you posted several times about O notation acting as if you knew what you were saying.  Doesn't that mean you were bullshitting?

O(1) means that resource consumption remains constant with input size (not including the resources required to represent the input).
O(X) means that resource consumption grows at a constant rate with input size.
O(X^1/2) means that the resource consumption grows at a rate of X^1/2 with input size.

Can you figure out the rest on your own?

[profitis]

Cumon mr sarkeizen if O1 is deterministicly time consuming due to two degrees of freedom and hence banned from quenco then what is O(X^1/2) and how much time does it consume(We doubt mr sarkeizen shall return to this thread)

[profitis]

'O(X^1/2) means that the resource consumption grows at a rate of X^1/2 with input size.'

Excellent. so a dead switch with only one degree of freedom of movement (o) is basicly that.since a single electron can be in one position and two positions at the same time we can allow for a 01 and 01/2 simultaneously.thus bbbv isnot violated because of heisenberg uncertainty where we can be technicly oo and o1 at same time