Kapanadze Cousin - DALLY FREE ENERGY

[Jeg]

So your 148m of wire, coiled up in 945 turns over 38cm space on a 5cm diameter tube with the bottom end grounded will start resonating  around 1Mhz.
Itsu

Itsu
I am aware of this fact. What I am saying is that for maximum voltage output, the 148 meters have to be the 1/4 of the total wavelength which corresponds to a frequency of 500Khz. If I am to use the 1Mhz frequency with my 148m coil, then Secondary's top will produce maximum current and zero voltage (ideally). Look at the attached image.

[itsu]

Jeg,

You have seen for yourself that your 148m kacher resonates at 1Mhz.
If you use a scope probe and move it from bottom to top alongside your kacher, you will see that the amplitude (keep same distance from coil)
will go from zero at the bottom to max at the top pointing to a ¼ wave voltage buildup.

So yes,  "the 148 meters have to be the 1/4 of the total wavelength", but in this case not for 500Khz, but for your measured 1Mhz.

Itsu 

[Jeg]

Jeg,

You have seen for yourself that your 148m kacher resonates at 1Mhz.
If you use a scope probe and move it from bottom to top alongside your kacher, you will see that the amplitude (keep same distance from coil)
will go from zero at the bottom to max at the top pointing to a ¼ wave voltage buildup.

So yes,  "the 148 meters have to be the 1/4 of the total wavelength", but in this case not for 500Khz, but for your measured 1Mhz.

Itsu

Itsu
Yes i see the 1MHz due to specific inductance and capacity characteristics. The point is if it needs to be lowered to 500KHz with a top load so to take out its maximum voltage.
We speak about a standing wave and its nodes-antinodes. I don't understand why it has to be different when using kacher drivers.
Thanks for sharing your experience anyway. 

ps. I just did the probe test as you described and confirms your suggestion. The question is why is that? Anybody? The image above suggests the opposite! I am going to search more for blocking osc.

[itsu]

Jeg,

in my mind, the kacher type of setup will auto adjust itself to a ¼ λ type of resonator which per default has its max amplitude at the top (bottom grounded).
So with or without the topload there always is a max amplitude at the top even when at different resonance frequencies, see drawing below.

By the way, for your secondary without topload (Fres = 1Mhz) to resonate at 500Khz, you will have to add a sphere topload with a diameter of 30cm / topload Effective Capacitance = 14.4pF   (using the javatc calculator)

Itsu

[Jeg]

So with or without the topload there always is a max amplitude at the top even when at different resonance frequencies, see drawing below.

Itsu
Thanks for the drawing

Lets suppose that we use a wire of 74m as a secondary and by inserting a top load we make it vibrate again at 1MHz like in the above case. How is that possible at the same frequency of 1 MHz both of the wires (148m &74m) to present max HV at their top sides as a quarter wavelength does?? Isn't that a paradox???

Any physicist here??