Kapanadze Cousin - DALLY FREE ENERGY

[mihai.isteniuc]

@all

Itsu was right. The probe was the real barrier. I have make a quick setup and after changing the probe with another, the ~10ns pulse has miraculosly change into a ~7ns pulse with ~1000V peak voltage. So I have to buy a decent probe.

Thank's Itsu for your inspired remark.

BTW: the diode used was a bridge rectifier - KBL406G (2 diodes from the bridge in parallel connection; datasheet attached).

Mihai

[d3x0r]

Right, "Keep It Short Stupid" principle.

On the back burner does not mean that i have put it aside completely.

F.I. i did rewind my L3 coil partially with another good quality new coax cable (RG-316 which has a copper cladded steel stranded inner conductor).
This coax is much thinner and 7 meters of it only covered 40% of the total coil, so it was asymmetric.
But the same pulse leakage was seen with this (again shorted) coax.
I will need to order about 20M to cover the complete coil.

something about ...


oh yes; Dally's is assymetric also.  In fact a length of his L4 is doubled back on itself also assymetrically....


He noted that his was foil, and if I remember right, his was more like a single conductor along a foil shield;  all of the shielded I have is also covered in braid.


Although, your homemade coax should do the trick there.  I wonder how exactly the electron flow looks in a good cylinder ( like as it's self inducting, it's going to cause more helical paths...)  and although the propagation is actually in a skin effect (so the outside skin is best right?)

Toroflux
For sale... ( I should make a better video that's more to the point of what I mean...)

This can be put on a string/rope, and will rotate in 2 dimensions as it moves; it sort of rolls along.... in a certain interpretation it's a image of the magnetic flux around a moving particle...

The modular approach of my setup enables me to quickly swap different modules and make modifications to the circuit.

I don't think this will bring any advantages but have no idea if this is simply done or takes elaborate electronics to accomplish

Regards Itsu

[verpies]

Can I ask you to share some tech info regarding the first driver from #947 post?
1st - what was the gauge of the wire used by you for the coils
2nd - the number of turns
3rd - diameter of the former
4th - have you used any ferrite cores and if so what type?
5th - what was the supply on L1?
6th - any other information that you will find useful it's welcomed.
7th - Also I would like to ask you if you can do a small test for me: if you replace the kd204 diode with let's say 1n5408 (if you have any) what are the best results?

1) 18AWG
2) 25turns (L1 perpendicular to L2 to minimize mutual inductance)
3) 4mm
4) No
5) 200V
6) MOSFET CMF10120, Driver UCC27511, 4:1 Fwd/Rev current ratio.
7) 380V @ 120ns

[verpies]

What do you think about the configuration from attachement?

When the pulse reaches the cental point it will branch 3-ways: left, right, up.
The resultant impedance of these three 50Ω coaxial cables will be like one cable having 16.6Ω impedance (50Ω/3).

This impedance mismatch will result in partial reflection of opposite polarity back down into the feeding cable.
The rest of the pulse's energy will be distributed evenly among the 3 branches.  The upper branch is terminated with the 50Ω resistive load thus no impedance mismatch exists there and the pulse will not be reflected from this far end. However the right & left branches will pulses from their far ends..

In the first case, the left & right branches are shorted at their far ends, which will result in reflection of the pulse. This reflection will have an opposite polarity to the forward pulse.

In the second case, the left & right branches are opened at their far ends, which will result in reflection of the pulse. This reflection will have the same polarity as the forward pulse.

The reflected pulses will eventually meet in the center, they will add up if left & right branches had the same length, and their combined energy will be sent back down into the source and up into the 50Ω resistive load. The energy of the reflected pulses will be shared equally by the upper and lower branch.

Because the two left & right branches have combined impedance equal to 25Ω in parallel (50Ω/2) and the reflected pulse is distributed equally into two up&down branches, also having 25Ω combined impedance in parallel (50Ω/2), then for the reflected pulses, there is no impedance mismatch at the central point and no further reflections will be generated into the left & right branches.  In other words all of the reflected energy from the left & right branches will be transferred equally to the upper & lower branch (the source).

[verpies]

I wonder how exactly the electron flow looks in a good cylinder ( like as it's self inducting, it's going to cause more helical paths...)  and although the propagation is actually in a skin effect (so the outside skin is best right?)

It looks like this: