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Overunity Machines Forum



Kapanadze Cousin - DALLY FREE ENERGY

Started by 27Bubba, September 18, 2012, 02:17:22 PM

Previous topic - Next topic

0 Members and 342 Guests are viewing this topic.

Hoppy

Quote from: d3x0r on November 24, 2014, 02:08:32 PM
Yup; that's the same... really one diode is the same as 2 with one side super high resistance... just uses capactiance of the diode instead...  (I guess) I mean a single diode also worked to get max differential across that cap.


I guess... without the load, how high can you get for a charge ?
-----

786V immediately across 10uF (2 x 20uF, 400V PIO caps in series).

I use two ultra-fast 4A diodes in parallel on heat sink.

d3x0r

Quote from: Hoppy on November 24, 2014, 02:17:16 PM
786V immediately across 10uF (2 x 20uF, 400V PIO caps in series).

I use two ultra-fast 4A diodes in parallel on heat sink.
need higher voltage caps.. but  786 : 800 from 2 in series... maybe they start leaking
786 to 203 is a large drop... are you using 220 lights or 110?  and are 220 lights double the resistance?  (2 110 in series = 1 220?)

Hoppy

Quote from: d3x0r on November 24, 2014, 02:32:39 PM
need higher voltage caps.. but  786 : 800 from 2 in series... maybe they start leaking
786 to 203 is a large drop... are you using 220 lights or 110?  and are 220 lights double the resistance?  (2 110 in series = 1 220?)

240V bulbs. Cold resistance of 40W bulb is 107R. I do not have 110V lamp to measure.

Void

Quote from: T-1000 on November 24, 2014, 01:45:59 PM
The capacitor is half discharged to critical point to the load then is left to recharge.
This is very important as current required to recharge capacitor is much smaller than to recharge from 0v.
This is why I posted info earlier to university page about capacitor charging.

Hi T-1000. The current does fall off as the capacitor charges, but the rate that the capacitor voltage increases 
also falls off. So even though the capacitor charging current is less, the voltage on the capacitor is increasing
slower and slower as you get closer to the max voltage, so a given amount of voltage increase takes longer in the
upper charging range. I don't think there is any reason to think the capacitor charges faster if only half discharging
the capacitor and then recharging it. See the capacitor charging voltage and current graphs attached. It would seem
that to get excess power out, something completely different is going on.

P.S. The second attachment is an actual scope voltage charge waveform using grenade to charge a 1uF cap.
It's rate of charge slows down quite a bit in the upper charge range, which is a normal capacitor charge waveform.
Nothing unusual seen in this arrangement.

All the best...

d3x0r

Quote from: Hoppy on November 24, 2014, 02:38:15 PM
240V bulbs. Cold resistance of 40W bulb is 107R. I do not have 110V lamp to measure.
I have a 60W, resistance is 21.7 approx...


so you have... 768V @ ( 2A ) ? or even 240V @2A is 480W? 


how many bulbs in parallel?  that just increases the current...
what is your input?  1KW?


capicitors need to be higher than the voltage they collect... because not only do they have the DC bias, they have a voltage wave common to both sides...