Kapanadze Cousin - DALLY FREE ENERGY

[AlienGrey]

Jeg, does your Rigol scope have math functions to multiply the current waveform by
the voltage waveform and then take the average of that product?

Void ask Tinsel K he will tell you how to do it!

[AlienGrey]

Hmm it won't work as it has major design floors there must be thousands who have no idea that have already made that device and got nothing
Oh and what film did you get that still from ?
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Color have you got this design to work ?  to me it's lacking stuff ?
and have you a pointer to your blog?

[Void]

Void ask Tinsel K he will tell you how to do it!

Hi AG. Yes, I know how to do it but i am not sure if Jeg's scope has
those math functions. All the best...

[Jeg]

High Void.
Yes Rigol can do the job. I just don't have a current probe. But anyway in this case I don't need it. I paralleled the two heater resistances and brought it down to 1 Ohm. Rigol shows 14V as Vrms and I trust it. I'll just try to verify it with the water heating method just for fun. Perhaps i'll record it.   

Regards

[Void]

High Void.
Yes Rigol can do the job. I just don't have a current probe. But anyway in this case I don't need it. I paralleled the two heater resistances and brought it down to 1 Ohm. Rigol shows 14V as Vrms and I trust it. I'll just try to verify it with the water heating method just for fun. Perhaps i'll record it.   
Regards

Hi Jeg, I see. You don't need a current probe to use that method I mentioned to measure the power.
A 1 ohm non inductive CSR should do as well, if the current is not too low, and if your circuit setup allows it. 
The problem with using the RMS reading on a scope for complex waveforms is the RMS readings
may well not properly take into account phase angle differences and whether the current is only
conducting part of the time. Using the method I mentioned should take all that into account, so should be
a more reliable way to measure the power.  I think it would be worth comparing using that
method just to see how the measured power compares to the way you were doing it, but that's
up to you.

I would be interested to see how you do your heat measurement calculations.

All the best...