Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[marathonman]

Finished Primary bobbin ready to wind.
Regards,
Marathonman

[marathonman]

creasysee;

  I am sorry for the late post i honestly did not see that post. it seems there is a laps in time when some show up. ?
congrats on the understanding of part G. it does take a leap of faith at first until one realizes what was taught in school about an Inductor is not entirely true. when used in an active position in a circuit with a moving positive contact the magnetic flux to current ratio is changing thus the increase and decrease of current flow plus the storing and releasing of potential in the system.
a lot of people thought i was wrong but my bench told me otherwise. a circuit has a certain amount of self induction so if you increase the self induction as per the amount of current, the opposing potential produced within the circuit, you get a current reduction in a linear fashion. Figuera used an active Inductor plain and simple.

my primaries were wound that way for the least amount of resistance as resistance leads to heat thus increased losses. they are wound up and back four times for a total of 8 layers with paper in between each set to ease the winding procedure. people still need to realize that part G controls the current NOT the primaries so they need to take advantage of this scenario and be wound specifically as electromagnets to get the biggest bang for your buck as to say. i used 14 awg wire for the primaries to take advantage of the low resistance yet handle the peak current at the height of the full on current. other wire sizes can be used i just happen to chose 14 awg.
Welcome aboard and i am glad part G made sense to you.
Regards,
Marathonman

[marathonman]

One must remember that the pressure between your primaries need to be maintained at all times. say i wanted to attain 1 kilowatt output that equates to 14.8 lbs pressure between the primaries at all times which is 7.4 lbs per primary.  now to induce movement into the secondary you have to reduce one primary and increase the other to get the sweeping action across the full length of the secondary. so let say i needed to reduce one primary 30% to get the sweeping action, that will reduce the 7.4 lbs to 5.18 lbs in the reducing primary. that means that the peeking primary must make up the difference to maintain the 14.8 lbs and that will be 9.62 lbs for the peeking primary.

the 14.8 has to be maintained at all times or the output will drop considerably. what most people do not realize is that in order to get that peek at the end of the rising primary the secondary feed back has to be in place. with out this feed back from the secondary there will be no peek at the height of the rising primary thus the output will never attain the 1 kilowatt output or what ever your desired output is.

Regards,

Marathonman

[seaad]

MM
How about the current through the part-G (coil)  when the brushes passes the question mark positions? in my proposed circuits (pic).

Regards Arne

[marathonman]

Since the current in the primaries are equal the output will be zero at that mark on both sides of part G peaking at set N or set S output.
see graph below.
the negative sign gets connected to the primaries and the positive side to part G. the negative sign i have on my part G is the secondary feed back to part G through a commutator that way both positive and negative stay their sign always. if Mr D has another way please feel free to pipe up.
Regards,
Marathonman