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Overunity Machines Forum



Single circuits generate nuclear reactions

Started by Tesla_2006, July 31, 2006, 08:15:00 PM

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0 Members and 16 Guests are viewing this topic.

Earl

@ R McGuiver

1- Try turning the diode upside down and repeat test.
2- Replace with second diode  and repeat test.
3- Turn second diode upside down and repeat test.
4- Replace with LED  and repeat test.
5- Turn LED upside down and repeat test.

What are the results of these 5 tests?

Earl
"It is through science that we prove, but through intuition that we discover." - H. Poincare

"Most of all, start every day asking yourself what you will do today to make the world a better place to live in."  Mark Snoswell

"As we look ahead, we have an expression in Shell, which we like to use, and that is just as the Stone Age did not end for the lack of rocks, the oil and gas age will not end for the lack oil and gas, but rather technology will move us forward." John Hofmeister, president Shell Oil Company

xee

@Inventor81 ,
Did you try reversing the polarity of the diode? Since there is no voltage across it, I assume the results will be the same. Perhaps heat comes from diode lead connected to ground. This could be checked by replacing diode with just a lead that is only connected to ground. Your results are certainly impressive, just hard to understand. Your experiment seems like the kind of test that leads to major new discoveries. Great work.

DrSimon

*Group
I wanted to find out if the heat in the diode was coming from conduction of the leads or a combination of this and the focus of heat from the small resistor at +/-10mW so I performed the following test using a UF4007. Crude yes but it did offer some information. The resistor is a Carbon Composition 2W +/-10%. The mags are in a small Styrofoam collar around the resistor. The connections can be seen in the picture.

What I found was a very slight increase in resistor heat (to be expected) remember it is a two watt unit. The test was run for four (4) minutes for five runs. The resistor was allowed to cool back to ambient temperature before each run was started. What was observed was an increase of +0.8C in the resistor and a -0.3C in the diode. The diode reading is well within the measurement error and I am sure it did not cool. So unless I am really doing it wrong it does not seem to work for me at this time. The voltage was indeed 9V and the diode connected to the ground or negative supply lead.

&&Edit: I forgot to say that there was NO detectable Beta above background. This was check with two very good instruments.


allcanadian

Here is something you may want to consider, a quote by Henry Moray.
QuoteWhen an elastic substance is subjected to strain and then set free, one of two things happen. The substance may slowly recover from the strain and gradually attain its natural state or the elastic recoil may carry it past its position of equilibrium and beyond, and cause it to execute a series of oscillations. In other words, there may be a continuous flow of energy in one direction until the discharge is completed or an oscillating discharge may occur, That is, the first flow may be succeeded by a backrush and succeeding backrushes, the oscillations going on until the energy is either radiated or used up in the energizing of the conductors

Now consider what you are doing, discharging a defined amount of energy in a capacitor in an infinately small period of time through a short conductor. This energy in the "carbon" conductor could radiate, it could heat the conductor or it could with the help of the capacitance display the properties of elastic recoil and oscillate. What is seldom considered is that the "rate of change" can be more important than the circuit potential and current flow and that a "single" impulse is always resonant with the circuit it is applied to while a forced oscillation may not be. I think it is very likely this is what is happening, the impulse from the capacitors through the conductor radiates a field at 90 degrees from the conductor and expells the permanent magnetic field from the secondary windings on the core. As well the carbon rod and capacitors form a super low resistance LC circuit which could oscillate at ultra high frequencies and could easily account for the "beta radiation". It is also interesting to note that Tesla is well known for his experiments with massive capacitor discharges through short conductors producing what he and others called "radiant energy" as energy is radiated from the conductor. This technology is very neat as we are not necessarily dealing only with conductors any more, we are producing fields which have unique properties determined by there frequency and potential. Yesterday I charged a 2200uF capacitor to 20v in two seconds using a single wire, the single conductor was 10 feet long and connected to one of Dr.Stifflers SEC oscillators, from the Dr.Stiffler thread. This is a good example of the misunderstanding we have have concerning field energy as most qualified people would tell me what I have done --cannot be done.
Knowledge without Use and Expression is a vain thing, bringing no good to its possessor, or to the race.

UncleFester

Not enough capacitance for low voltage run = Not enough current. Has anyone read what Juan said? His statements coincide with data already collected. At 12 volts you need hundreds of amperes of discharge across the rod. The formula is there, you just need to read it.

On a different note, the carbon rod does get hot.....something that will have to be dealt with later.....

Please go back and re-read what Dave posted from Juan, there is no need to re-invent the wheel.