Single circuits generate nuclear reactions

[Koen1]

The basic idea is that at the flux levels required to recoup your input energy, you would kill yourself within 30 minutes.

The basic idea is also that it is an over unity process and that is impossible according to just about any established physicist.
So I am not certain how much you can say with certainty about a pocess that does not follow the assumed standard "rules",
flips energy conservation the bird, and gives us out significantly more than we put in...

You WOULD experience physiological effects after a few tens of seconds - and even after a second or two, you would have sunburn-like injuries to the skin exposed to the device.

Thus, it is not the beta which is providing the "overunity".

Or so we hope to be able to assume on the basis of known processes that do not
produce OU.

[twosox]

@AbbaRue

any joy on locating a suitable circuit diagram ? there is one in the pdf file that Stefan posted from juan, but is
it a 'single shot' or continuous operation circuit? dunno. i'm twiddling my thumbs now waiting for parts.

[leo48]

@Stefan

I removed the email addresses from this guy Juan,
cause he was running scams lately...

So I don?t know how valid these informations are.

Regards, Stefan.

How post my MP
tanks you
leo48

[leo48]

Hi all
I did a test:

and this is the result:

bar coal is diameter 4 mm and 25 mm long and sending
impulses from 20V.
The upper line is the input
the bottom is the toroid
leo48

[allcanadian]

@Xee

Does that mean you think the meters are not even any good for detecting low levels of beta rays when they are used in changing strong magnetic fields? It seems that you think there never were any beta rays at all, just false readings due to magnetic fields. Is that a correct reading of what you are saying?

I think the misconception may be the type of fields generated, the beta detector uses ionization to detect radiation so magnetic fields could have little effect on it, but if we are talking about an electrostatic impulse or wave having a high frequency then the detector would see this as radiation as it produces ionization on "any" conductor including the geiger tube.

@inventor81
I think we are on the same page, I have been doing tests with a "copper" conductor/rod as well. It's funny how everything comes back to one person ---- Tesla