Free Solid State/mechanical energy

[Charlie_V]

... You put the current 90 degrees out of phase between the primary and secondary.

2. How exactly?
3. Is it important +90 or -90 degrees? Why?

A: You measure the inductance of the secondary coils (or calculate them with an induction formula).  You then figure out how large your capacitor needs to be to cancel out this inductance (the formula to figure this out is [0 = (2Ïâ,¬f)?LC -1], where f is the frequency, L is the calculated inductance, and C is the capacitor value.)

On the primary side you will want to make sure that your frequency is the same as what you use for your secondary.  There is actually a way of "tuning" the primary but I wouldn't worry about it for starters.  Ideally you would want to tune the primary so that the phase was truly 90 degrees apart between the circuits.  However, just tuning the secondary is good enough.   

+ or - 90 degrees doesn't matter.

... You make sure the self inductance of the secondary is neutralized by placing a "condenser" (capacitor) in the secondary circuit.

4. Why?
5. Is not affecting the main goal with 90 degree phase shift from primary? Why?

A: Secondary circuit is in resonance.  The primary circuit should also be in resonance but the difference is that in the primary (assuming you tuned it) the resistance would be almost infinity (the formula for the primary is [infinity = 1/((2Ïâ,¬f)?LC -1))].  Primary has infinity resistance (all voltage) and secondary has zero resistance (all current) at resonance. 

The resistance between the two circuits is mismatched.  This means the power will be reflected (aka what you put into the system will be returned).  I'm sure your wondering why.  Imagine you are in a racket ball room.  The front wall (where you hit the ball against) is usually really hard right?  You smack the ball against the wall and the ball bounces back.  Lets assume that the wall is made soft.  Now when the ball hits the softened wall, it doesn't bounce back as much.  The softer the wall is made the less the ball will bounce back.  At some point, the ball will smack the wall and instantly drop to the ground.  This is the point that maximum power was transfered from the ball to the wall.  There will be no return.   

This is the same as resistance in a circuit.  If the resistance of one side of the circuit matches the resistance of the other side, the power can go through (i.e. the ball hitting the wall and dropping instantly to the ground).  When the resistance is mismatched, you get reflections (the ball bouncing back after hitting the wall).

... This increases the current in the secondary.

6. If you answered "resonance" at question #3, then why current and not voltage?

A: Zero resistance means large current, small voltage. 

... The current makes the rotor spin.

7. How?

A: Magnetic interaction between the secondary coils and the rotor.  Basically magnetic induction.

... Since the phase between the primary and secondary is 90 degrees, power used is returned.

8. Why?

A: Already answered.

... The device runs on unity.

9. Why?

A: If the power you put into a system is returned, then no power was lost.  Ideally, you have a unity motor. 

Don't believe in lizard people.

A: Anyone who can convince me without fancy names and theories will be filtered out as non lizard people. If you can, use the association of electricity with water flowing in pipes. Please assume you are a science teacher; can you explain this to a child?

I hope my nothing I've said was too fancy - I don't want to be a lizard man. 

[brnbrade]

Hi all

Look at this link. The good stuff.  http://etc.usf.edu/clipart/20100/20156/sepexcdynamo_20156.htm
Have many concept used in these devices.
Very, very simple to building.

By 

[nat1971a]

Can I order another couple of jugs of beer for the table......


Sorry Barbosi I hope i didnt offend anyone....i am just putting my thoughts out there for everyone.....but one must ask the question why bother to have the armature at all and why rotate it. And why neutralise the armature coils.

[Trump]

Charlie_V

You are right on top of things, I like your reasoning and hopefully others do also. It is stuck in my mind on what Erfinder said loud and clear in his last message.

When you realize that we are using the currents manifested in the secondary windings only, this will mark the moment that you begun to change your thinking, and have received your first true taste of the force Tesla was working with. Erfinder

So the primary windings are not being used, but are a part of the switching, correct me Charlie if I am wrong on this part ,but they are still a part of the circuit and have a part to play in the 90 degree switching from the way I see it.


****Side Note****
In classical circuits a resistance is often used to slow down or use up some of the current flowing through a line.  The same holds true here the only difference is that a capacitor plays the role of the resistance, and at the same time a filter!  It is not about charging nor discharging the capacitor as there is no break point in the circuit! Erfinder
****

Again from Erfinder, the capacitor,  NOT a variable capacitor, just tuned as I put it capacitor, to also FILTER as Erfinder puts for RESISTANCE. Nothing more.


Regards


Trump

[nat1971a]

Hi All,

I think I need another beer. Its been a long week researching this....

hmmm i shall try and explain what i suspect is happening with the rotation of the armature.

If we have a neutralised current (the neutralised armature coils) that is rotated fast as we have here in Tesla's patent. This then attracts the neutralised ether to it like a whirlpool would suck in all the water. This would compress the ether to a point where it must radiate it out. This radiated out neutralised current is transferred to the neutralised secondary via resonance.

Cheers,

N.