increase OU of captret

[dequadin]

did anyone have using filament to feed electron to the captret in a close system(like vacuum tube)?

Setup:
tin the tube outside with black colour.
captret(highly negative)
positive terminal-> connect to the positive to the load
negative terminal -> to the negative of the load

To begin with, feed electron using filament connecting to a small circuit, then remove.
if the self charging effect is valid, the captret must be charged up with negative ion.


Thinking this way...  High RE(low density of -ve) -> Low RE(high density of -ve)= battery
1. Atmosphere is slightly Low RE. Captret terminal connected here
2. positive terminal of the cap tend to move potential to same as the atmosphere.
3. negative terminal tend to stay Low RE
when connecting captret terminal with much negative atmosphere(Much Lower RE), positive terminal become High RE compare to the captret and push ion to negative terminal. Resulting in draining RE into the cap

So, cap voltage(density different) mean easiness of become Low RE that we really need

[dequadin]

Actually, I have build a system to make a really big tendency to grab +ve charge, and put those charge into a big capacitor.
big capacitor captret terminal connect to the negative terminal of a capacitor for storage, all -ve and +ve connect to the positive terminal of the storage one.

for the storage capacitor, short captret and the negative terminal, the voltage between the storage capacitor grow up no longer in hour, but few second. (<3s +1mV)

the big capacitor and the storage one (250V 470uF)

[dequadin]

I found it!

But i am not sure. it charge my 2.7V 63kF to 0.5V just a second without battery. i short it down to zero and it grow up to 0.5V again in a second!
I have used a Digital and a analog voltmeter to test it, the analog one showing 0.4V , digital one showing 0.6V and growing up.

i am trying to make one to light up 1 LED


It is beyond my understanding of physic!! No heat released in that such a high power charge up.......
no matter how many time i discharge, once the circuit is closed, my cap bank just charge up in a second

[dequadin]

My tube provide me about around 1.1V right now. When I reduce the pressure inside the tube, the tube seem to give me much higher voltage output from a output terminal.

When I compare the voltage different with the ground, the ground act as a positive side. It is too hard for me to purify the output and amplifier the output to a higher voltage, since it has a strange behaviour of the output, just like a extremely high frequency(cannot be measure by any device) pulse voltage

[dequadin]

I can now getting more the 3.4V~3.7V from my tube after shield with PVC, look really like the same as T.H. Moray one.
However, my tube doesn't require any battery.
After I can build something produce more than 12V and light up something like 40W LED, I will share this tube.

Also, I based on the same theory that already made something interesting like this, enjoy.
http://youtu.be/YuqiijUpvxY