Has anyone seen Lasersabers new motor runs on 1000uf cap

[gyulasun]

Hi Lasersaber,

Could you measure the DC resistance of one of your coils, out of the 12 coils? Of course if you happen to have an L meter, the inductance value for a single coil would also be useful.

Thanks, Gyula

[conradelektro]

Actually the 1uA motor in this first video had no diode in use.  See: http://youtu.be/Esphle_MsXI  The resistance comes from the 42 AGW wire itself.  At anything under 5V I would use no diode at all and tune for the lowest possible uA current draw.  Once you have achieved a current draw under 5uA with no diode then start experimenting with diodes.

@Lasersaber: what is the DC resistance of your coil (or all six coils in series) in your six coil motor?

Each of my six coils has a DC resistance of 90 Ohm, all six in series therefore about 540 Ohm.

Greetings, Conrad

P.S.: Power draw calculation for my pulse motor (over the resistor which is parallel to the diode):

Average power draw with a 6.8 K resistor is about 40 µA, with 2.2 K resistor it is about 120 µA. It also depends on the speed the rotor turns.

The reed switch is about 20% of the time ON.

[conradelektro]

I did some scope shots over a 10 Ohm shunt to calculate average power draw of my little pulse motor at 1 Volt supply Voltage (no diode, just the shunt, see circuit diagram in attached drawing). And a scope shot over the Reed switch to show its ON-time (between 20% and 30%, depending on Reed switch position and turning speed of the rotor). I have chosen a 1 Volt supply Voltage to make the rotor turn relatively slowly.

My Multimeter measurement of about 500 µA was confirmed.

Why does my pulse motor draw about 100 times more power than Lasersaber's six coil motor?

Is it the impedance of the coils?

Is it the mechanical set up (specially the crudeness of the build)?

It can not be the ON-time of the Reed switch, because it could not be made 100 times shorter!

Comments appreciated.

Remark: The rotor can not turn faster than a few 100 rpm because it is badly balanced. With a supply Voltage of about 6 Volt it jumps out of its bearing (terminal speed reached).

For further details and a photo see this post http://www.overunity.com/13523/has-anyone-seen-lasersabers-new-motor-runs-on-1000uf-cap/msg362615/#msg362615

Greetings, Conrad

[gyulasun]

Why does my pulse motor draw about 100 times more power than Lasersaber's six coil motor?

Is it the impedance of the coils?

Is it the mechanical set up (specially the crudeness of the build)?

Hi Conrad,

Thanks for the measurements.  I think Lasersaber's coils has much higher impedances (DC resistance and inductance) than yours, this could be main reason for his 1 uA current draw. 
Later I will comment if something useful occurs to me.

Greetings,
Gyula

[Farmhand]

I think when you connect the diode in parallel with the coils, this may need a different reed switch position than when the diode is in series with the coils.  The parallel diode keeps up the current in the coils when the reed already is OFF, so the reed needs to be in a position where its own ON time is less than in the case the diode is in series with the coils. IF you readjusted the reed to the parallel diode, then please disregard what I wrote.

Thanks for the measurements. You think now the waveform across the switch is not worth checking by the scope (when the diode is in series with the coils)?

Greetings, Gyula

I would like to give my 2 cents on this point, it is one of the things I showed in the tests I did with my motor, when the coils are snubbed by a diode in parallel the current stops immediately as I showed, however when the coil can discharge into a higher voltage (such as a charge battery or some mechanism to allow a similar effect)  the discharge then causes current to continue after the switch (reed or whatever) is turned off. In my experiment the current waveform showed that the current ceased immediately when the coil was snubbed by a parallel diode, but continued for some time when a charge battery or other mechanism is used. I can show the shots but they are already posted in the other thread I guess I'll have to look for them where they are posted and provide a link.

When the coil is snubbed by the parallel diode the input is less than when a charge battery is used, adjustments need to be made to keep the input the same when these things are changed, Gyula is correct about that, but I do disagree slightly on the effects or the reason/cause. I'll show why. I'll need a minute.


The shots are at the bottom of the post, linked below. Top shots are clamped (with the snubber diode) bottom shots are with a charge battery. The bottom of the "drain" shots are angled because of where the scope ground is placed (not at circuit ground) the mosfets switch properly, it's just because of where the circuit is scoped. The top traces are the current through the motor coil, the bottom the mosfet drain.
http://www.overunity.com/11350/confirming-the-delayed-lenz-effect/msg359288/#msg359288

If I can clarify anything I just wrote please say so. 

Cheers

I think whats happening is when no snubbing diode is used the voltage is very high at the drain for some time, the effect of that exactly I can't say in conrads setup. But I think it would cause an effect different to snubbing and also different to a charge battery. With enough input it would destroy the mosfet. The snubber or the charge battery will save it but they will have different effects.

I think the scope shots show quite clearly the effect and I don't see any way it can be disputed. I did the experiment, I urge others to do it also and concur or disagree with my results, I can demonstrate the test on video. But that should not be necessary.

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