Energy from the Ground - Self powered generator by Barbosa and Leal

[captainkt]

@cheors, as a.king21  said, in the UK the earth is the neutral the neutral is the earth clamped at both ends. There is only one live wire from grid, often a concentric cable is run to houses which has only one red conductor in the center then the outside is armoured  steel earthed, neutral is connected to this at the house and at the power station. Called PME.

Regards
Keith

[Zeitmaschine]

Time for new experiments. This is about a very strange behavior of a simple electric circuit. High voltage with nearly zero current attracts electrons from ground and passes them through a spark gap (that plasma jet melts ceramic). I don't think this behavior is completely in accordance with the textbooks.

Captor De Elétrons Da Terra

It works also without the antenna, but then the spark is not that strong. Ground is not really necessary because there are a lot of free electrons already in the wires. Also there is not this violent sparking when the diode is shorted or the connected capacity is too high.

The high voltage transformer actually consists of ten small 230/24V transformers connected together. When that transformer is connected in step-down mode, a primary voltage of 234V generates 19.5V secondary voltage. Hence the ratio of that transformer is 1:12. So in step-up mode 302V input should generate 3624V RMS, that's 5110V peak-to-peak.

The length of the spark is 4 to 5mm, that implies a voltage of 4 to 5KV. This matches the roughly 5KV p-p coming from the transformer. What not matches is the high current obviously going through the spark gap. The 12V DC current coming from the battery is 3A without spark and around 4A with spark. This calculates to 4A times 12V equals 48W total power consumption.

Since the high voltage at the spark gap is around 3624V RMS this then calculates to 48W divided by 3624V RMS equals 0.013A (13mA) at best. Not considered any power dissipation of the inverter and the transformer itself.

Now you decide if the current going through that ear-deafening spark gap is just around a maximum of 13mA or not rather a lot higher.

If we calculate just the 1A DC difference between spark and no spark, the calculation looks like this: 1A times 12V equals 12W. 12W divided by 3624V RMS equals 0.0033A (3.3mA).

Now the counter calculation: Shorting the secondary of that high voltage transformer via a 270KOhm resistor (or even directly) in series with a spark gap means 3624V RMS divided by 270000 Ohm equals a current of 0.013A (13mA). That's the same 13mA value like calculated above, but I have to dim the lights in the room to see that faint tiny spark (almost noiseless) which is created by that 13mA/3624V RMS.

As it looks, this setup consists of a capacitor that provides high current with low voltage and a transformer that provides high voltage with low current. The result of this seems to be a mixture of high voltage with high current (amplification of power).

Any questions and suggestions?

Further readings:

The Work that is Created by Means of Potential Field - Alexander V. Frolov
Advanced Energy and Propulsion Systems based on Chronal Reaction Method - Alexander V. Frolov

By the way: Figure 5 seems to be the theory about the Perendev Magnet Motor; Figure 6 the theory about the Quantum Energy Generator (QEG).

[pomodoro]

Are you really, REALLY, sure that a spark to the metal in the last drawing draws no current from the primary??  I'd check that with an oscilloscope on the primary before believing Frolov.

[captainkt]

Hi zeitmaschine, where are you putting load in your captor circuit, across the spark or in series with the spark or somewhere else? Also I am not sure how long inverter will last with high voltage up against output, When I try to mix voltages in my circuits inverter blows.

Regards
Keith

[Zeitmaschine]

Are you really, REALLY, sure that a spark to the metal in the last drawing draws no current from the primary??  I'd check that with an oscilloscope on the primary before believing Frolov.

Absolutely SURE. The primary should be connected to an inverter and a 12V battery. So the 12V DC (!) ampere measurement is accurate to the mA. Don't measure the AC on the primary directly, it is completely messy due to the sharp spark pulses.

Hi zeitmaschine, where are you putting load in your captor circuit, across the spark or in series with the spark or somewhere else? Also I am not sure how long inverter will last with high voltage up against output, When I try to mix voltages in my circuits inverter blows.

The spark is the load. Replacing the spark with an incandescent lamp (high-ohmic) will not show anything unusual. That lamp then just shines dim and flickers. Maybe connecting an arc lamp is the better choice.