Acme Fixer's highly efficient Joule Thief help needed.

[Legalizeshemp420]

There are 9 minor divisions across the shot you show. That makes 9 x 0.0000005 sec = 0.0000045 sec or 4.5 microseconds for the full screen. There are 17 full periods shown. 17/0.0000045 = 3.78 MegaHz. 

It's easy to misplace decimal points, for sure, I do it all the time, and maybe I did again. But whenever possible on an analog scope, use as many screen divisions and peaks as possible to do your frequency calculations. Accuracy improves with more cycles and more divisions.

You lost me.

In that shot I was counting the middle reticule until I saw the same pattern with the next wave.  I counted that at 2,4,half way between, 6,8,div.  So, .5?

[TinselKoala]

18 on each side of 20 or 22ga wire or possibly 24ga but no smaller wire.

I can't measure the inductance value of it myself though.

Sure you can. You have a scope, right? Set up a tank circuit with a known capacitance, poke it with a little jolt from a power supply and measure the ring frequency. Then calculate the inductance based on the capacitor value and the measured frequency. That's how inductance meters do it.

[Legalizeshemp420]

I know what I meant was I don't have a way to constantly poke it since I can't freeze a capture like I could in a DSO.  Because I can't do that I would need something that repeats.  I saw the circuits but do not have the parts here to replicate.

[TinselKoala]

You lost me.

In that shot I was counting the middle reticule until I saw the same pattern with the next wave.  I counted that at 2,4,half way between, 6,8,div.  So, .5?

Look at the screen graticule markers. There are nine full divisions across the scopeshot you showed. That means there are 9 x 0.5 microseconds across the whole screen. Right?

How many peaks are there across the whole screen? Since the first one is aligned with the first leftmost graticule line, it is the "zeroeth" one and doesn't count. SO there are 17 peaks across the screen until you get to the rightmost graticle marker shown. You have 17 full cycles in 4.5 microseconds.

Your own value, 1 cycle in 0.25 microseconds, also yields a value of 4 MHz, not 400 kHz.

[Legalizeshemp420]

Look at the screen graticule markers. There are nine full divisions across the scopeshot you showed. That means there are 9 x 0.5 microseconds across the whole screen. Right?

How many peaks are there across the whole screen? Since the first one is aligned with the first leftmost graticule line, it is the "zeroeth" one and doesn't count. SO there are 17 peaks across the screen until you get to the rightmost graticle marker shown. You have 17 full cycles in 4.5 microseconds.

Your own value, 1 cycle in 0.25 microseconds, also yields a value of 4 MHz, not 400 kHz.

Ahhhh, we came to the same result only via a different path PLUS that damn misplaced decimal point, lol.  btw, 4mhz makes more sense than seeing that many patterns on my 20mhz scope for a 400khz signal.

Now, UGH 4mhz?  WaTaH?!?  lol