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Even more simplified experiment to show OU using artificial gravity

Started by nybtorque, November 07, 2013, 09:21:56 AM

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nybtorque

Lets consider the experiment below. A bottle opener and a garlic press, connected with a thin thread through a ring. Hold the ring between your fingers and spin the bottle opener around to reach an equilibrium where the the centrifugal force of the rotating bottle opener keeps the garlic press in a constant position.


If we assume that the mass of the garlic press is 200g and the bottle opener mass is 50g and the radius of rotation is 20cm we need a rotational speed of 14 rad/s, i.e. 2.25 Hz.


To keep this rotational speed and equilibrium we need 0.2J of kinetic energy invested in the rotation.


This is all fine. But lets say we increase the rotational speed a little. What will happen?


Of course the garlic press will begin to move upwards since the centrifugal force will become larger than the gravitational force pulling the garlic press down... Actually, in theory an infinitesimal increase of kinetic energy (a one time energy input) in rotation of the bottle opener will be enough for a continuos movement (acceleration) against gravity for the garlic press and thereby an continuos increase in potential energy, i.e. infinite overunity...


Enjoy!


NT


 








telecom

Quote from: nybtorque on November 07, 2013, 09:21:56 AM
Lets consider the experiment below. A bottle opener and a garlic press, connected with a thin thread through a ring. Hold the ring between your fingers and spin the bottle opener around to reach an equilibrium where the the centrifugal force of the rotating bottle opener keeps the garlic press in a constant position.


If we assume that the mass of the garlic press is 200g and the bottle opener mass is 50g and the radius of rotation is 20cm we need a rotational speed of 14 rad/s, i.e. 2.25 Hz.


To keep this rotational speed and equilibrium we need 0.2J of kinetic energy invested in the rotation.


This is all fine. But lets say we increase the rotational speed a little. What will happen?


Of course the garlic press will begin to move upwards since the centrifugal force will become larger than the gravitational force pulling the garlic press down... Actually, in theory an infinitesimal increase of kinetic energy (a one time energy input) in rotation of the bottle opener will be enough for a continuos movement (acceleration) against gravity for the garlic press and thereby an continuos increase in potential energy, i.e. infinite overunity...


Enjoy!


NT



Hi,
can you please draw a diagram of your experiment since I have a hard following of what should be rotated and what should rise
against the gravity . Also, how you have calculated the forces, using a centrifugal force equation or Lagrange?
Regards.

fletcher

Quote from: nybtorque on November 07, 2013, 09:21:56 AM


...snip... To keep this rotational speed and equilibrium we need 0.2J of kinetic energy invested in the rotation.


IINM .. the 0.2 joules of energy invested to maintain equilibrium of forces is the amount of energy inputted to overcome windage [drag forces] of the bottle opener & rotating wire ?!

N.B. for a constant velocity [rpm] if we know the drag force [proportional to the square of the speed] & the circumference of the circle at radius 20cm then f x d = joules of energy expended - since the drag force is a function of air mass [e.g. Force in Newtons = Cd.1/2(air density).velocity^2.frontal area] then according to Newton's Laws we must input muscle energy equivalent to the energy lost to air drag.



This is all fine. But lets say we increase the rotational speed a little. What will happen?


Of course the garlic press will begin to move upwards since the centrifugal force will become larger than the gravitational force pulling the garlic press down... Actually, in theory an infinitesimal increase of kinetic energy (a one time energy input) in rotation of the bottle opener will be enough for a continuous movement (acceleration) against gravity for the garlic press and thereby an continuous increase in potential energy, i.e. infinite overunity...



Force [N's] = mass x acceleration

Centrifugal force = Centripetal force = m.v^2/r

Gravity force = Weight force = m.g where 'g' = 9.81 m/s^2

1. A small increase in muscle input energy will break the equilibrium of forces & increase rpm & velocity of the bottle opener [bo] - this will also increase air drag proportionately since it is a factor of air velocity squared.

2. the Cf's acting on the bo will increase by the square of the velocity so that the Cf is greater than the weight force of the suspended mass.

3. since Cf's [mv^2/r] > mg the suspended mass will rise upwards gaining Pe [mgh in joules].

4. the radius of rotation will increase to greater than 20 cm.

5. the Cf will reduce because of a greater radius.

Questions:

a. does the Potential Energy [Pe] gained by the suspended mass ever exceed the excess muscle energy input required to maintain the new & higher rpm ?

b. is there ever a situation using a mechanical assembly of any sort where Pe gained is greater than the input energy ?




lumen

Take a look at this torque increasing drive wheel, as the blue disk rotates with all the attached gears and weights, the weights will want to move outward.

The outward movement rotates the center gear with increased torque dependent on the RPM of the disk and the value of the weights.
The system cannot produce back torque or it would be able to do work from gravity and this is impossible, but the increase in torque could be valuable if used correctly.
If an electric motor was used to turn the disk then the weights would simply fly outward and the center gear would rotate the same speed as the disk, but as a load on the center gear increases, like from a generator under load, the weights would want to rotate back inward to the 90 degree position as shown. This applies no additional load on the driving motor.

Now, if the generator was connected to a load like the grid, where the load could sink very large currents, a circuit could be built to keep the weights at the 90 degree point by varying the load on the generator. The motor is now free to spin the disk faster and faster, further increasing the output without any additional load but with huge additional output.

Centrifugal force put to work.

telecom