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Overunity Machines Forum



The Magneformer-lenzless transformer ?

Started by tinman, November 10, 2013, 08:34:54 AM

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0 Members and 2 Guests are viewing this topic.

Newton II


When a permanent magnet is brought near a coil conducting a AC wave,   it (magnet) simply vibrates indicating that it is experiencing attraction during one half cycle and repulsion during other half cycle of AC wave.   But  the field of PM cannot affect the current flowing in the coil.   

A permanent magnet's  field can be considered as a standing AC wave with north pole as positive half of the cycle and south pole as negavitive half of the cycle.   So  a permanent magnet can affect the AC wave in the coil only if it is rotated and coupled (or synchronised) with the magnetic field produced in the coil by AC wave.

I think this coupling principle is made use of in rotary transformers but no PMs are used.

http://en.wikipedia.org/wiki/Rotary_transformer



MileHigh

Tinman:

It's very late so I will just cover this one topic and respond more later.

QuoteLets do the math on the maximum power that could be put into the system from the signal generator-there is no rocket science here.
The SG is set at 4Vpp,so 2 volts on the forward side.
There is a 220ohm resistor on the base of the transistor.
The duty cycle is 23%.
So the maximum power/watts that can be achieved is .018 watts
.018 x 23%=.00414 watt's.
I think your splitting hairs there MH,concidering the P/in is 132mWatts.
But just for arguments sake,we will change the P/in to 136mWatts.

Here is the big problem:  You are shifting the goalposts.  In your second clip you made a nonsensical test for checking for the possible power injected into the circuit by the signal generator.  Do you agree with my point or do you have something to support what you did in the clip?

You are crunching numbers above but there was no discussion of crunching any numbers in the clip.  You also make a mistake but that is not important.  The only issue is what transpired in your second clip.  I just commented on what I saw and you didn't respond to what went on in your clip.

MileHigh


tinman

Useing the scope was to show the small signal coming from the SG,which is a visual way for me to show the small amount of power being supplied by the SG-and you have to agree,it is very small.
Also ,please feel free to point me out to my mistake-as this is how we learn. Im just as good at missing things as anyone else. If you are refering to how the transistor distributes that signal power,please remember i have  a diode across the base/emitter junction.

I would like to know what you think is being disipated by the 18 ohm resistor,as far as the scope shot go's.
I am also drawing up a quick scetch for you and all to have a look at,and post your opinions on as to what happens throughout 1 cycle.It will be in 2D,so wont be anything fantastic,but it will show what im am asking.

tinman

@ MH and all
Useing the picture below,i would like to ask the following questions.
Lets asume that the electromagnet has just enough power flowing through it to equal the strength of the field of the permanent magnet.Both magnets are of equal distance from the inductor core. So once the electromagnet is switched on,the field within the inductor is neutral throughout.

So first,what happens when we switch on the electromagnet?
Is there a BEMF or lenz force applied to our electromagnet coil?
Will the electromagnet still use the same amount of power ,with and without the inductor and PM being there?.

second-what happens when the electromagnet is switched off?-becomes open circuit.

Once the electromagnet switches off,and the field of the PM becomes the field within the inductor core-where or what is the BEMF or lenz force between?.

If we load the inductive kickback from our electromagnet coil,as in charging a battery,or placing a low value resistor across the output,what happens to the magnetic field within the inductor?.