Reactive power - Reactive Generator research from GotoLuc - discussion thread

[poynt99]

I would say double check your probe connections and invert settings on both channels of the scope. Maybe your CH1 is already inverted for example.  If those check out, put a diagram up here and double check your connections to that.

[tinman]

I think what the input bulb IS good for is indicating the amount of current in the primary. If I recall correctly.

[picowatt]

To poynt99 or anyone who wants to take a go at it

I have a toroid which I wound myself in Bifilar on a Ferroxcube toroid core. It is under test connected to a sine wave output of my SG set at 4.33 Mhz.

My 200Mhz DSO scope is set to DC Coupling and I'm using my non Inductive 2 inch long nichrome wire which I adjusted to 0.1 Ohm. Both scope probes are connected in the standard way to measure power. Ch 1 is voltage and Ch 2 is current.

It seems from the scope math that 3.8W is being returned. I have attached both Non Inverted and Inverted of Ch 2 scope shots so not to have another debate on that matter and also many samples of each versions.

I have checked my DSO scope against Thane's Tektronic before returning it to him just to make sure it was accurate and found mine to be better as far as comparing math data between Ch 2 inverting or not. So I don't think this is a scope error.

Let me know what you think

Luc

Luc,

Are you sure your 2" length of nichrome is "non-inductive"?

I do not know how the nichrome composition would affect the inductance calculations, nor do I know your nichrome wire's actual diameter.

However, a 2" length of .05" copper wire has about 40nH of inductance.

The reactance of 40nH at 4.33MHz is a bit over 1 ohm.

PW

[tinman]

I think what the input bulb IS good for is indicating the amount of current in the primary. If I recall correctly.

I dont think they are very good for that at all,infact my experiments show the complete opposite.The effect verpies showed,can be done with a simple pulse motor,where we can get the output bulb to light up bright,while the input bulb remains unlit.And this is not done by haveing the input bulb in series with the drive coil,but having the input bulb in series with the power supply and large cap's. The power to drive the pulse motor then is drawn from the cap's. So any power the motor uses must be a stedy DC flow through the bulb.

[tinman]

Looking at the circuit below,how is it possable for G2 to light up brightly,and G1 to remain unlit?.How is the flow of steady DC power through G1 on the p/in side, less than the flow of steady DC power through G2 on the P/out side?.