Reactive power - Reactive Generator research from GotoLuc - discussion thread

[Farmhand]

The only way I could think of testing the circuit to see if it can deliver real power (hopefully at no cost) was to build a generator and see if it causes a load to the alternator and prime mover once the circuit is connected.
To my surprise it didn't cause a load (if tuned correctly) to the prime mover and delivered real power.
From that I concluded we can extract power from a generator and that maybe we can do the same from the grid without losses to the grid provider.

So there was no input to the prime mover ? Just because the load caused no noticeable effect to the prime mover means next to nothing. What matters is what was the actual input and what was the actual output.

The important thing is in my opinion that the input and the output are still in question.

What I don't get is if it is actually free energy then why can it not be done with a battery and true sine wave inverter, until extra energy is shown I don't see valid gains.

Cheers

[poynt99]

@poynt99
I don´t think that the channel 2 in your diagram needs to be inverted as both scope channels have the same ground location in the circuit...right ?

Actually, CH2 does need to be inverted (by the scope, not physically) in order to retain proper phase between the voltage and current.

[poynt99]

Stefan,

I've already offered a plausible explanation for the noisy wave forms Tim is getting.

At 60Hz, the capacitive reactance of a 7uF capacitor is about 380 Ohms! So we have a high-pass filter effect here, and a significant level of noisy harmonics etc. are coming through. The noise is always there, we just don't see it when the grid is being measured without any high-pass filtering.

[poynt99]

I just did a second test:
http://www.youtube.com/watch?v=iVE6Nit0_p8

/Hob

Hmmm, meters...puzzling indeed.

May I suggest Hob that you use your scope to measure the actual phase difference between the voltage and current as I showed in my diagram. Then with the amplitudes you can calculate the true input power.

Then of course you can do the same with the resistive load to see the output power.

Am I the only one that sees the elephant in the room?

[gotoluc]

Hi poynt,

sorry for staying out of the discussion. I needed to do this to stay focused on my tests in hopes to better understand the circuit with my way of understanding which is non conventional I know but this is what allowed me to come up with these ideas.

So, don't take it personally. Your knowledge is and has been very helpful.

I see you have posted the below diagram for probe position, which are my probe positions. However I see you say to invert Channel 2 (current probe) is this the correct way?... and do you wish I test it this way and post the results.

Thanks for your time

Luc