Mathematical Analysis of an Ideal ZED

[MarkE]

MarkE, the CYCLE would need to be from State 1(x) to State 2 to State 3 and back to State 1(x).  At least that is the goal of my Analysis.  Reciprocating on any one leg of a cycle is a pointless Analysis exercise, IMHO, regardless of the truth of your statement.

You can define a cycle as including whatever sequential states you want, so long as you always work your way back to the starting state by the end of each cycle.  No matter what you do:  The machine is fundamentally lossy.

The further problem with the Ideal ZED having pulled a vacuum in the pod chamber at State 1X is that it could NOT reset (without added Energy) from State 3 back to State 1X simply by venting the water from the pod chamber by "pulling the plug."

What defines whether the state is reachable or not is whether or not there is an intermediate lower energy state.  If there isn't, then the water should drain completely before reaching State 1X.  It is then a matter of closing the drain when the water has drained out, and the system will develop the vacuum as it works its way to State 1X.

So State 1X may also be an unrealistic start and end State for a simple Analysis.  Any ideas?  I'm wondering if a new State 1Y is necessary for the start and end of the Ideal ZED cycle?

Yes, there should be a State Y where the pod chamber is empty and the pressure on the pod chamber floor is positive or zero.

[MarkE]

Well excuse me for showing my work.

What this proves is that you have a hard time with information that is not in your exact style.

Is the answer correct and is that the same answer I posted prior to your answer sheet,, yep.

Maybe I should of put it this way instead of putting in those extra spaces of separation

.25π×44^2×(32.5−10)

PLUS

(.25π×(44^2−42^2)×(10−1))

EQUALS

35427.740354532

Is this "π" supposed to be pi?  It renders as a lowercase "n" in my browser.  If it is pi, then I apologize for not seeing that.

then

35427.740354532×.000001×9.789 = 0.34680215N

Showing how one solves a problem is often more important than the solution value.  Take for example where I used the wrong value for pWater that got LarryC so excited.  The work showed that the math was correct but for the constant value.  Constants are easy to fix.

What you did here is not what you did in your spreadsheet.  Because if you had followed the same process in your spreadsheet, you would have found that your audit results match the correct results that are in the R4 spreadsheet. 

The problem that we keep coming back to is that you keep making mistakes and then claiming that because your results don't agree that the R4 spreadsheet is wrong.  In the some ten days that you have been claiming that there are multiple "obvious" errors in the R4 spreadsheet, you haven't actually identified a single one.  You have instead assembled a bunch of errant calculations of your own.  It was you who stated to effect that you "just keep trying different things" to see if the numbers will match.  If you set-up the algebra based on your understanding of physics, then filling in the values is the last and least important step.  Instead of showing your work, you keep posting screen shots of numbers.  It's meaningless palp.

Showing one's work is very important.  The R4 spreadsheet including the drawings should make it easy for anyone to follow along, check the work, and find that it is correct.

[TinselKoala]

Yep, that pesky "pi" symbol in the default font is a problem, hard to read. Looks very much like the lower-case "n". Even "bolded" it's hard to tell them apart.

π
n

ℼ

That last one is from the "common" character set, "Double struck small pi", U+213C.

∫ ⚝  ㊷ ䷔

Did those chars display for you?

[MarkE]

No problem with the miss,, I actually realized that I should of at least enclosed each part to make that easier,,

=cir_mm2_to_mm2_1*Riser3ODCirArea_1*(ST2_AR7Height_1-ST2_AR6Height_1)*0.001

this is what I am doing in the spreadsheet calculation for volume in cc of the riser

That gives you the top cylinder slice in the same way as you addressed the quiz question.  Your units are a little strange:  mm³/1000 but that can be fixed with a constant.

=cir_mm2_to_mm2_1*Riser3WallCirArea_1*(ST3_AR7_Height_1-(ST3_Uplift_1+VerGap_1))*0.001

This is where you went wrong.  You are counting the entire riser wall here as in the R4 spreadsheet, but you already counted the part above the AR6 meniscus.  Using the method you used in the quiz question it would be:
=cir_mm2_to_mm2_1*Riser3WallCirArea_1*(ST3_AR6_Height_1-(ST3_Uplift_1+VerGap_1))*0.001

IE taking only the portion of the riser wall that is below the inside meniscus, since you have already counted the part that is above the meniscus.

The way that you have been doing it, you have double counted the portion of the riser wall that is above the AR6 meniscus.

This is for the Extension into the water after lift,, again, volume in cc

I do believe that this is what I did and what you have shown.

No, you have been double dipping just as I have told you for several days now.

[MarkE]

Yep, that pesky "pi" symbol in the default font is a problem, hard to read. Looks very much like the lower-case "n". Even "bolded" it's hard to tell them apart.

π
n

ℼ

That last one is from the "common" character set, "Double struck small pi", U+213C.

∫ ⚝  ㊷ ䷔

Did those chars display for you?

I see what looks like two lower case "n"s, some box with a 213c in it an integral sign a star a cirle with a 42 in it and something that looks like a sandwich.