Recover energy from gravity

[rc4]

An idea with half torus inside water. All the system is under gravity. I compute forces F1 and F2 and they don't depend of radius (R), only of height (h) in the integrale. So this would say I can suppress bottom surfaces (grey color) so the weight is reduced too. Normally, surfaces must be compensated by volume of air, but here it's lower volume. I can move up or down all the system (water+air) the energy is not the weight by distance. Like F1=F2 all the time I can let at bottom air volume without force, and this suppress surfaces at bottom.

The result is always 2h, for any R.

[rc4]

small error, it's more that: 2h/pi, don't depend of R

[Gabriele]

So you are saying F1=F2? Are you sure of that?

[rc4]

arf, this don't work with homogenous liquid, maybe if density change

[rc4]

New idea with container of water with an object with air inside. It's like a weighing scale, but here I use the difference of distance for change the torque. If container can be like drawings, the air object give a difference of torque. It's possible to change the position of air object because container of water is always at horizontal. Red line is a rope that attach the air object to the stem.