Recover energy from gravity

[rc4]

I simulated with Spiceopus, it's the same result:

Transformer

vV1 0 3 dc 0 ac 1 0
+      sin(0 {12*1.414213562} 500 0 0 0)

rR4 1 0 1e-05 vresR4 
.model vresR4 r(  )


rR3 5 0 1e-05 vresR3 
.model vresR3 r(  )


rR5 8 0 1e-05 vresR5 
.model vresR5 r(  )

K1 LL1 LL2 0.9
K2 LL2 LL3 0.9
K3 LL1 LL3 0.0001

rR2 0 7 6 vresR2 
.model vresR2 r(  )


rR1 0 2 9 vresR1 
.model vresR1 r(  )


lL3 7 8 1

lL2 2 5 1

lL1 3 1 1

.end

Sure, iron will saturate but even in transitory the sum of energy seems to be not at 0.

[rc4]

nobody tested this circuit ?

[Gabriele]

I don't have tecnical instruments to try this circuit...why don't you try by yourself?

[rc4]

I tried it but fuse from alimentation is destroyed each time, the current increase very quickly in the primary ! Why others people don't simulate and watch what's happened ?

[rc4]

1 image/ Another idea with capacitors, use N plate capacitors (or others shapes, cylinder for example). Charge in step 1 with plates in front of them. Discharge in resistor with plate far away, this increase energy (not the charge but the field), so the voltage.  Use plate - from N capacitor and plate + from N+1 capacitor for example. It's not a linear law and I think it's better to user small larger of plates. Or do the reverse STEP2->STEP1. Maybe discharge 1,3,5,7, etc. and after discharge 2,4,6,8,etc. like that first capacitors give same energy than alone but after the voltage increase.

Something must change when I use 2 differents plates, because the cycle could be:
s1/ charge capacitors
s2/ move one plate, need energy
s3/ discharge, if I discharge same energy at s1, where goes energy at s2 ?

2 image/ use N/N+2 capacitors

3 image/ charge all capacitors, and after increase red diameter, it's easierto increase because red surfaces repuls themselves.

c9.png: when capacitors move away, there are attractive forces (magenta) and repulsives forces (black). It's easier to separate capacitors than alone.