Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[MileHigh]

Okay as a follow-up to the previous comments about the fact that the toggling value of the inductance can not possibly be a source of energy, then what are you left with?

The answer is yes, the rotating rotor does indeed change the value of the inductance, but that is not what is ultimately driving the LC resonator and pumping power into it.

The reality is that at the same time this is happening, one can assume some temporary induced magnetism in the spinning rotor is *fighting* with the induced magnetism in the toroidal core.  That *fighting* is better known as Lenz drag.  During the rotor blade passes, there is a "North - North" type of induced magnetic repulsion happening that is against the turning of the rotor, and/or, there is a "North - South" type of magnetic attraction happening that is against the turning of the rotor.

This Lenz drag is the mechanical source of power that pumps up the LC resonator and puts more energy into it.

At the same time, this increased energy in the LC resonator gets pumped into the light bulb load via the magnetic coupling of the toroidal core.

Therefore, the ultimate cause for the Lenz drag is the light bulb load.

The proof of this was already shown in one of today's clips.   It's the part where you see the light bulbs brightening then going out, brightening then going out, roughly once per second.

What is that telling you?   It's telling you that the motor speeds up then the QEG hits LC resonance.  That makes the light bulbs light up.  That causes Lenz drag and the motor slows down.  The motor slowing down means you lose LC resonance.  Losing LC resonance means the light bulbs go out.  The light bulbs going out means the Lenz drag disappears.  The Lenz drag disappearing means the motor can start speeding up again.  And so on, and so on...

The proof of Lenz drag and going in and out of resonance is right there for all to see.

MileHigh

[TinselKoala]

Here is a Spectrum Analysis of my MOT QEG test device.

Note that my rotor RPM is in the 1,500 RPM range... But my Electrical Resonance is in the 29Hz range.

My MOT Inductance swings from 6H to 12H and Resonating Capacitor is 2.5uf

From the Spectrum my test devices Mechanical Resonance is in the 225Hz range with a second peak in the 500Hz range.

Luc

Heh.... 1500 RPM is 25 Hz. 25 x 29 is 725. 500 + 225 is.... 725. Numbers don't lie!


( but they do joke around a lot.)

[F_Brown]

All:

Note 0.010" of an inch is roughly the thickness of a sheet of paper.  There is not a chance that the QEG could be built to that dimensional size, not to mention 0.001" which is ridiculous.  If that's in the manual somewhere that's laughable.  Now notice saying "laughable" is not malicious bashing, it's simply a true statement.  Note we haven't even been discussing tolerances.

F_Brown,

I am not sure if you are simulating with ideal components or component models that include hidden parameters to make them "real world."  In reading your statements there is one thing I want to make clear about the switching of the inductance value, where you toggle back and forth between two values.  For starters that's a pretty cool trick that you are doing with the sim.  The big point is that just the act of dynamically switching the value of an inductor that's in a circuit in the "real time" of your simulation cannot be a source of energy.  It simply can't happen.  So I am not sure how you are getting increasing resonant oscillations in your simulation.

Here is something for your consideration, and I will assume we are working with ideal components here:  Your circuit is [12-volt battery] -> [2-ohm resistor] -> [ inductor(t)] ->  [Ground]

Let's say the inductor(t) toggles between 2 Henries and 4 Henries every 30 seconds.   What will the sim show?   How will it handle the abrupt change in the value of the inductance?  It's effectively a discontinuity in the value of the inductance, will the sim be able to cope with it?

Let's forget about the sim for a second and crunch it in our heads.  Let's assume ideal components.  Do you know what will happen when the inductance toggles in value?  It's an important question because if you do know then great, but if you aren't sure, then how can you be sure your sim is running correctly?

MileHigh

In my sim the inductance parameter varies in a smooth, continuous, sine-wave manner, rather than a discontinuous step wise manner.  I read a paper on parametric excitation just enough to be able to model it.  I have yet to read it through enough to be able to discus how it build energy in the system.  I just know it does it does so in an exponential fashion.

The rest of the components what few there are, have real world parasitic values except for the cap.  The ESR of the capacitor I expect would be negligible small, especially if it was a high-quality film-foil cap.

[MileHigh]

Thanks for the extra information.  The fact that you make the inductance value vary like a sine wave is very impressive, and of course it's presumably a much better approximation of what is taking place in the QEG than a step function.

When you switch to a variable mechanical inductor the answer as to what happens is essentially instantly available and seems obvious.  I already mentioned it.   Hint hint...  lol

Just for fun, let me see if I can get through doing it mathematically on 'paper.'   I am going to enter rarely visited waters...

The example circuit to analyze the problem is trivial - it's just an ideal inductor shorted by an ideal wire.

The formula for your inductance as a function of time:

L(t) =  (sin(omega * t) +2)     [inductance varies between 1 and 3 Henries]   Note - I am avoiding a divide-by-zero problem

Let's define the initial conditions and use something simple to illustrate the problem:  When the inductance is 3 henries, say the current is 5 amps.   That means you have 37.5 joules stored in the coil under these conditions.

Everything is ideal, so no energy is lost.   We just need to solve for the current as a function of inductance.  Since the inductance also varies with time, you effectively are also solving for the current as a function of time.   The voltage across the coil is always zero, and that may help us to simplify things.

Let's take a peek at how things look when the inductance is 1 henry.  You still have to have 37.5 joules stored in the inductor therefore the current has to be:

E = 1/2 L I^2
I^2 = 2E/L
I = sqrt(2E/L)

Therefore when L = 1 henry,  i = 8.66 amps.

[MileHigh]

Okay, so...

We are looking for i(l(t)),  the current as a function of the time-varying inductance....   And we know that the energy stored in the time-varying inductance is a constant.   We also know that the voltage is always zero.

l(t) =  (sin(omega * t) +2)

dl(t)/dt = omega * (cos (omega * t))       [not needed]

E = 1/2 L i^2

37.5 = 1/2 * (sin(omega * t) +2) * I^2

75 = (sin(omega * t) + 2) * I^2

i^2 = 75/(sin(omega * t) + 2)

i(t) = sqrt((75/(sin(omega * t) + 2))    - [equation for the current as a function of time]

Let's try punching in the values:

When the inductance is 3 henries, i = 5 amps, that checks out.

When the inductance is 1 henry, i = 8.66 amps, that checks out.

However, I still haven't solved for i(l), the current as a function of inductance,  and I am too tired now.