The Bessler Wheel, mystery solved.

[Marsing]

edit-     Youtube is Ok,   thanks

[gurangax]

hi..     i think there is option in your program to save in different resolution, and it will be easier.

thank.

Im sorry I dont think there is, but I already uploaded it to youtube.


regards

[gurangax]

Bessler said:
"He will be called a great craftsman, who can easily/lightly throw a heavy thing high, if one pound falls a quarter, it shoots four pounds, four quarters high."


Depending upon the interpretation, "if one pound falls a quarter, it shoots" either "four pounds four quarters high" or "each pound one quarter high".


I'm not discrediting your findings but your principle does not match Bessler's own description of the principle.  Your fall distance appears to be over 7 times the raised height.  You may have found "a" solution but it does not sound like you found Bessler's solution.


p.s. You were correct, our solutions are not the same.  Luckily my discovery is safe for the moment.

I think I found the meaning of this. It is possible what he meant was, let say 1 pound weight falls down the lever with distance a quarter, this causes imbalance to the wheel so the weight now rotates with the wheel a distance of 4 quarters from bottom to top of wheel. this is logical and doesnt go against the laws.


regards

[zoelra]

Marsing said:
"zoelra, is your finding fit with those words?"


Yes I can make that happen and it does not violate the conservation of energy law.  It is made up of simple movements and leverage.

There is no way to know if the amount of weight and fall/lift distances Bessler mentions is what he actually used in his wheels, but a mechanism that is capable of producing that type of effect with the values he specified would have significance.  To be clear, I'm not saying the mechanism I'm presenting is Bessler's solution, but it is a possible solution because it does match his comments.


I'm basing the information below on the ratio interpretation "if one pound falls one quarter, it shoots four pounds, four quarters high (each pound shooting one quarter high)".  The other interpretation would just require a modification of the mechanism parameters.

Start with a lever (like the one shown in the picture below) with a one pound weight on the right side and a four pound weight on the left side.  Both weights are equidistant from the pivot point.  If you know how to make the one pound weight on the right side feel like 4 pounds, then due to the symmetry, any drop in that weight will result in an equal rise of the weight on the opposite side of the lever.  So there you have it, "when one pound falls one X, it shoots four pounds, four X high" (each pound shooting one X high).  X being the distance dropped which could be a quarter of an inch, a quarter of a foot, a quarter of the wheel height, a quarter of a turn, or any displacement as long as the design allows.  Now all you have to do is figure out how to make that one pound weight feel like four pounds.  That's where lateral thinking and ingenuity comes in.


[EDIT]  Also note that the drawing I have included is a simple illustration to make the point and NOT the actual mechanism.  I should also add that in this example, just over one pound on the left is required to reset the one pound weight on the right, the remaining weight would be the "applied load" on the mechanism.  I see this mechanism as a prime mover, one of many, shifting weights to the overbalanced position, with those shifting weights being the "applied load".  Each mechanism would be oriented in the z-axis.  Remember in MT13, Bessler said the wheel would be good for running if someone was at the top of the wheel to lift the weights with lightning speed.

[MT]

Regarding your video. It shows a small weight dropping a large distance and a big weight rising a small distance. I can't seem to find the magic.

Hi gurangax,
Thanks for posting the idea. It really seemed you have it with all the theater around but as others also pointed I would also not be so sure. The idea may produce sounds similar what witnesses heard but I think the wheel will not pass 9o'clock in production phase.
In your first video for example your crossbar is 6kg which is lifted say 1m , this makes 60J GPE.
Your weight on lever is 1.3kg not considering weight of lever itself. If we assume crossbar is being lifted 1m then longer lever arm is looking at picture about 3m. Then weight start at 12o'clock have 39J GPE.
You let it fall 3 m to the 3o'clock then during lifting the crossbar another 3m below the rotation point. This movement only costed 78J.
No I assume you want to use the crossbar builded leverage to get also the lever with weight back to 12o'clock.
No way... Sorry.


Marcel