Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Lasersaber strikes again. A joule thief king ?

Started by hoptoad, May 01, 2014, 02:54:40 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

scratchrobot


conradelektro

Quote from: scratchrobot on May 20, 2014, 03:31:33 PM
My take on Lasersabers circuit, running on a 100uf cap at 9v.
https://www.youtube.com/watch?v=nDP1XuUUZf8

@scratchpot: I guess you used a MPSA18 transistor and the circuit as given here http://laserhacker.com/?p=410 ?

Trivial calculation for your circuit:

100 µF  *   9 V = 0.0009 As (charge at start Voltage)
-100 µF * 0.5 V = 0. 0.00005 As (charge at stop Voltage)
0.00085 As in 150 seconds (2 minutes 30 seconds) --> 0.00085 / 150 = 5.6 µA on average

Great achievement, congratulations. I saw the coil specs in your video info, thank you for specifying the details.

Greetings, Conrad

scratchrobot

Quote from: conradelektro on May 20, 2014, 04:32:46 PM
@scratchpot: I guess you used a MPSA18 transistor and the circuit as given here http://laserhacker.com/?p=410 ?

Trivial calculation for your circuit:

100 µF  *   9 V = 0.0009 As (charge at start Voltage)
-100 µF * 0.5 V = 0. 0.00005 As (charge at stop Voltage)
0.00085 As in 150 seconds (2 minutes 30 seconds) --> 0.00085 / 150 = 5.6 µA on average

Great achievement, congratulations. I saw the coil specs in your video info, thank you for specifying the details.

Greetings, Conrad

Yes i used the mpsa18 and your calculations seem acurate :)
Thanks

conradelektro

Quote from: Vortex1 on May 20, 2014, 12:23:00 PM
Greetings Conrad

Tell me what inductance and ratio you would like me to simulate in each of the coils, maybe something similar to what LS is using. I already have a circuit that has a 1:1 ratio, 50 mH each, but it can be changed. See attached.

green =collector V
blue=baseV
red=LED current

@Vortex1: thank you for publishing your very interesting circuit. I am always impressed if something is done in a well documented way together with a simulation. I will come back to your nice circuit once I am done with LaserSaber's circuit.

If it is not too much work for you I would like to ask for the following:

Please simulate LaserSaber's circuit as given here: http://laserhacker.com/?p=410

- you could omit the three 1N4146 diodes if it is easier

- the MPSA18 would be important

- as coil please use my coil: see the attached drawing, the core is the following

http://at.farnell.com/ferroxcube/etd59-31-22-3c90/ferrite-core-half-etd59-3c90/dp/3056430?Ntt=3056430
FERROXCUBE - ETD59/31/22-3C90 -  FERRITE CORE, HALF, ETD59, 3C90
Farnell Order Code: 3056430
Manufacturer Code: ETD59/31/22-3C90

My goal:

- I want -30 Volt peak at the base, which windings ratio would achieve that (at 9 Volt supply Voltage)? (Now the ratio is 1:3 and the peak is about -15 Volt). In other words, the signal from the secondary should have an amplitude from -30 V to + 30 Volt (60 Volt peak to peak) at 9 V supply Voltage.

- What happens if I double the windings (while keeping the ratio) ? (I want more current in the signal, but the peak should stay at -30 V)

- I have enamelled wire with 2 mm diameter (31 Gauge) and 4 mm diameter (26 Gauge). If necessary I could get different wire.

So, my aim is to find windings which give me a peak of -30 Volt at the base (from the secondary) and a bit more current in the signal from the secondary as I have now (all at 9 Volt supply Voltage). I hope I specified the requirements well enough. I do not know how much current is in the signal now, but it seems a bit too weak.


My coil as it is now:

- now I have 29 turns (one layer) as a primary, 5.5 mH, the wire has 0.6 mm diameter but a very thick insulation, it has in total a diameter of 1 mm (the layer fills the whole width)

- now I have 145 turns (5 layers) as a secondary, 145 mH, same wire (1:5 ratio)


Planned new winding:


- 1 layer of 0.4 mm wire as primary (will have about 70 to 80 turns)

- 6 layers of 0.4 mm wire as secondary (will have about 420 to 480 turns) (1:6 ratio)

- a last layer of 0.4 mm wire which I can add in series to the secondary to get a 1:7 ratio

Could you simulate that (at 9 Volt supply Voltage)?  (I want to have a -30 V to +30 V and reasonably strong signal on the secondary)


Last question: I have to learn this simulation business, do you happen to know from where I can download a useful version of LTSpice (for Windows 7)?

Greetings, Conrad

conradelektro

Quote from: TinselKoala on May 20, 2014, 12:38:23 PM
Dark Alchemist's circuit meets with my approval.

DALM, using MPSA18 or BC337-25.

@TinselKoala: I know I could search for the DALM circuit, but do you have a link to the circuit or a drawing at hand?

What is the power requirement of your DALM inplementation (roughly)?

I saw the inductance measurement, thank you, that helps.

Greetings, Conrad