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Akula eternal lantern 4

Started by MenofFather, June 01, 2014, 01:15:57 PM

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MarkE

Quote from: forest on March 12, 2015, 04:14:39 PM
MarkE


The problem is when device has output wires carrying high frequency currents of many amps.A shield like copper tube around wire ?
Forest, if you have a closed volume of metal, then currents flow on the inside surface of that metal.  Those currents make a magnetic image that is opposite and very nearly equal to the field that induced them.  So if you have a voltage generator sealed up in a metal box where the box itself is one of the conductors and a wire inside of the box is another of the conductors to a load resistor that also connects to the metal box, then what happens is that metal box creates an image (nearly) identical to the field from the wire.  So at that interior box boundary the two fields cancel and what gets outside is zero.  In reality the cancellation isn't quite perfect because of the finite resistivity of the box material.  That means that the exterior surface of the metal carries virtually no net high frequency current.

MarkE

Quote from: synchro1 on March 12, 2015, 05:38:34 PM
@MarkE,

You're a nauseating and obnoxious fraud. Get a life!
Is that your best effort at a reasoned argument?

synchro1

Quote from: MarkE on March 12, 2015, 05:49:54 PM
Is that your best effort at a reasoned argument?

@MarkE,

Start a new thread. The current thread topic here is "The Led Generator"! You're running a "Faraday Cage" snout rut through it.

forest

Quote from: MarkE on March 12, 2015, 05:49:21 PM
Forest, if you have a closed volume of metal, then currents flow on the inside surface of that metal.  Those currents make a magnetic image that is opposite and very nearly equal to the field that induced them.  So if you have a voltage generator sealed up in a metal box where the box itself is one of the conductors and a wire inside of the box is another of the conductors to a load resistor that also connects to the metal box, then what happens is that metal box creates an image (nearly) identical to the field from the wire.  So at that interior box boundary the two fields cancel and what gets outside is zero.  In reality the cancellation isn't quite perfect because of the finite resistivity of the box material.  That means that the exterior surface of the metal carries virtually no net high frequency current.


Device I'm working on is a high frequency few kW power generator with output wires to power resistive heaters inside second chamber.I guess I should enclose those wires in copper tube(s) and connect all chambers together then to ground to eliminate EMI.

MarkE

Quote from: forest on March 13, 2015, 04:55:34 AM

Device I'm working on is a high frequency few kW power generator with output wires to power resistive heaters inside second chamber.I guess I should enclose those wires in copper tube(s) and connect all chambers together then to ground to eliminate EMI.
You could, but that would be entirely unnecessary overkill.  If you generate DC output to the heaters then ordinary EMI filters can easily attenuate the high frequency noise.