Inertia Drive project. RFDD.

[tinman]

Tinman, I see you are spamming the boards everywhere, I cannot accept this insult to the intelligence of gravity device initiates.

I already had an idea for  clever and directable (decoupled) thornton drive, wich needed no gears and was far more solid and could had had a longer arm.

I never even considered it worthy of my time, a mere afterthought, not necessary to me.

And there you are, running around with mere shit as if it was gold.

Oh dear
Have you missed a dose of your medication again Army ?
It actually sounds like you have smoked waaaay to much of your piece pipe. I see no spaming from me,but i do how ever,see lots of dribble post from your self.Your failure to see what im trying to show,is proof that you have no idea about the simplest of machines or devices.

Now run on back to the med box,and get yaself a fix.

[ARMCORTEX]

There is not enough room on the servers for both of us Tinman.

Your thread is not as good as mine and you have more response.

I cannot tolerate this

[tinman]

There is not enough room on the servers for both of us Tinman.

Your thread is not as good as mine and you have more response.

I cannot tolerate this

Thats because people here can sort out the crap(yours) from those who spend the time experimenting ,and posting real result's(mine).

So once you are gone,there will be plenty of band width for me lol.

[lumen]

I see this a bit different.
It looks like a vector problem because you are simply combining two directional forces.
If jets A and B were the same, then this results in a jet C at the vector quantity of A and B (45 degree with twice the volume)
The new vector C still contains the original forces of A and B, and to capture this would generate the same opposite force as if A and B never intersected.

[MarkE]

I see this a bit different.
It looks like a vector problem because you are simply combining two directional forces.
If jets A and B were the same, then this results in a jet C at the vector quantity of A and B (45 degree with twice the volume)
The new vector C still contains the original forces of A and B, and to capture this would generate the same opposite force as if A and B never intersected.

Given two vectors:  [Xm, Y0, Z0] and [X0, Yn, Z0], the sum  results in a magnitude of (m² +  n²)^0.5 and a direction atan(n/m), but enither the Xm nor the Yn are lost  The sight gag here is that the scale reads the Xm force even though water propellent does not leave the system.