Slayer driven neon-producing DC via resistor ?.

tinman · August 21, 2014, 09:34:33 AM

Video uploading now.
But my guess ,after looking at the scope-i see an AC offset of about 250-300mV from the neon/cap circuit. I would say that this offset is additive over a number of pulses,until a maximum voltage is obtained in the cap. But my only question is-why dose the voltage in the cap only rise when i add a resistor in series with the neon and cap? the resistor is non linear,and i turned it around to make sure of that.

I'll leave the last bit of the post as is,but i just went and swaped the neon around,and no difference-still a DC voltage in the cap of same polarity.

MarkE · August 21, 2014, 09:41:30 AM

Quote from: tinman on August 21, 2014, 09:34:33 AM
Video uploading now.
But my guess ,after looking at the scope-i see an AC offset of about 250-300mV from the neon/cap circuit. I would say that this offset is additive over a number of pulses,until a maximum voltage is obtained in the cap. But my only question is-why dose the voltage in the cap only rise when i add a resistor in series with the neon and cap? the resistor is non linear,and i turned it around to make sure of that.

I'll leave the last bit of the post as is,but i just went and swaped the neon around,and no difference-still a DC voltage in the cap of same polarity.

DC amplifiers like the ones that are in your voltmeter are susceptible to RF noise. Some meters do better than others.

tinman · August 21, 2014, 09:56:00 AM

A look across the cap with the scope.

https://www.youtube.com/watch?v=lxhIVwvTo2Q&list=UUsLiBC2cL5GsZGLcj2rm-4w

MarkE · August 21, 2014, 10:13:17 AM

Quote from: tinman on August 21, 2014, 09:56:00 AM
A look across the cap with the scope.

https://www.youtube.com/watch?v=lxhIVwvTo2Q&list=UUsLiBC2cL5GsZGLcj2rm-4w

That shows that the noen is acting as a leaky diode. When it is connected through the resistor, the resistor unloads the weakly rectified source and the average capacitor voltage rises.

tinman · August 21, 2014, 10:24:31 AM

Quote from: MarkE on August 21, 2014, 10:13:17 AM
That shows that the noen is acting as a leaky diode. When it is connected through the resistor, the resistor unloads the weakly rectified source and the average capacitor voltage rises.

I thought that aswell,but as i wrote above,i went and turned the neon around,and no change in voltage polarity in the cap???.

So 1 thing i can think of,is that the cap itself can accept a charge in one direction better than in the other direction. So next i guess i go and swap the cap around,and see what happens. I dont think this is the case though,as i have tried many cap's,and get the same result.

The only other thing i can think of,is the effect that the resistor would have on the electric cables them self from the neon. Could the magnetic field around the cable with the resistor in series ,be weaken'd,while the other is not-resulting in a stronger field around that cable?.