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How to make a gravity over balance wheel spin! Probably not OU but interesting t

Started by nwman, October 06, 2014, 03:57:39 PM

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Your Thoughts?

No it will not work at all.
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Maybe it would work.
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Yea, Nwman..... You're the coolest!
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Total Members Voted: 5

Low-Q

Buoyancy happens due to pressure difference. It happens in all bodies, even on a steel ball in water. However, the mass density of steel is higher than water, so the ball will sink. You could likely used steel balls in your experiment. Same result.

When you spin the tank, pressure builds up at the walls and push the pingpong balls angular toward the surface - no longer vertical but obliquely toward the center. So no buoyancy vertically anymore. So there you go. Nothing happens to the "ferris wheel" inside the tank.

Vidar

Low-Q

Quote from: nwman on January 27, 2015, 03:20:49 PM
You are correct. It will take a bit of energy to get the water up to the sides. The question really would be then," How much energy is needed to "keep" the water up on the sides"? This may be a lot less according to the First Law. ?

Would I be correct in saying that once it is at speed it should only take enough force to overcome the friction of the bearings it's spinning on, wind etc...? The water shouldn't be any different then having the same amount of solid weight in the same position spinning. For example if you have a bicycle tire spinning, once it is up to speed you only need to add a small amount of energy to maintain the speed.

In regards to friction, this approach would only work if there is an abundance of OU, if at all. Thus, friction would have an impact but I don't see it being the big reason why this wouldn't work... if it would work.... ha.
It does not require energy to keep the water up the wall - in general. In an ideal scenario with no friction, the water itself will keep the spin going, because when the water wants to go down, the mass is going to the center and increase the spin. The increased spin will push the water up the wall again. Ofcourse, this happens at the same time, so you will not notice any change.


Vidar