Sum of torque

[dieter]

By "handle" I meant what do you do with friction. Electromagnetic device is a bit vague, but ok. I guess the wheels do not really have to touch eachother.


The gyroscope will resist rotation, but when a torque is applied (as the big wheel rotates), then I guess the sum of torque 1+2 will cause "recession", eg. in the direction into the picture (or against the surface of the big wheel), see also youtube videos about "Eric Laithwaite".


BR

[EOW]

Yes, the gyroscope cause a precession. The support turns around the axis Z. The gyroscope cause a precession around the axis Y.  In the lab frame reference the wheel and the gyroscope don't turn around the axis Z, it's a translation, its angular velocity around the axis Z is 0. The problem is to give the rest of the force that the gyroscope can't cancel to the support. The gyro can't be fixed to the support with an axis because the axis will absord all forces and the gyroscope will receive nothing. It's possible to imagine the wheel with an axis to the support and the gyroscope is "floating" in the wheel. Forces are gave to the gyroscope not the wheel, like that the force the gyroscope can't cancel will give to the wheel.

[dieter]

"Floating" ? 


BTW. aren't the arrows of F in the wrong direction? 


BR

[EOW]

I think forces are good but it's the trajectory the problem, the distance change when the gyro turns.

A new idea with 2 supports:

Support1 and Support 2 are turning clockwise at w around the white axis
On the Support1 there is the Pulley1 with the radius 3R, the Pulley1 is turning at 2w clockwise (lab frame reference), the Pulley1 is turning at w in the lab frame reference
On the Support2 there is the Pulley2 with the radius R, the Pulley2 is turning clockwise at 4w (lab frame reference), the Pulley2 is turning at 3w in the lab frame reference
The Pulley2 is a brake, it transforms the mechanical energy to heating, the energy from heating is 4FRwt, because the Pulley2 turns at 4w and the radius is R
The Pulley1 receives the energy from a motor fixed on the Support1 (the motor is not drawn). The motor needs the energy -3FRwt and the Support1 receives a counterclockwise torque that lost the energy -3FRwt
The sum is not 0, it's -2FRwt. If the Pulley1 and the Pulley2 are fixed to the same support, the support receive a clockwise torque that give the energy 2FRwt, here with 2 supports, the force F and -F works at the same value in one round and cancel themselves.

I drawn different positions.

[EOW]

I corrected my message

Support1 and Support 2 are turning clockwise at w around the white axis
On the Support1 there is the Pulley1 with the radius 3R, the Pulley1 is turning at 2w clockwise (lab frame reference), the Pulley1 is turning at w on the Support1 frame reference
On the Support2 there is the Pulley2 with the radius R, the Pulley2 is turning clockwise at 4w (lab frame reference), the Pulley2 is turning at 3w on the Support2 frame reference
The belt turns because the radius goes from 3R to R and the angular velocity goes from w to 3w on the pulley
The Pulley2 is a brake, it transforms the mechanical energy to heating, the energy from heating is 4FRwt, because the Pulley2 turns at 4w and the radius is R
The Pulley1 receives the energy from a motor fixed on the Support1 (the motor is not drawn). The motor needs the energy -3FRwt and the Support1 receives a counterclockwise torque that lost the energy -3FRwt
The sum is not 0, it's -2FRwt. If the Pulley1 and the Pulley2 are fixed to the same support, the support receive a clockwise torque that give the energy 2FRwt, here with 2 supports, the force F and -F works at the same value in one round and cancel themselves in one round.

It's possible to use something else than the brake. It's just for have the force F. Here the energy is destroyed. For created energy, turns Support 1 and Support2, turn Pulley1 and Pulley2 and brake the Pulley2, it gives 4FRwt from the brake and it cancel -2FRwt from the Pulley1 (if the pulley has a mass).

I added 2 points A and B for look the angular velocity. A is fixed on Pulley1, B is fixed on Pulley2.