New cell type? NANOCRYSTAL OXIDE

[profitis]

Printer-plates or school-lab-magnesi ribbon is fine.weigh exactly 20-200 milligram on a scale and then put into cell.calculate faraday-equivalency and proceed.magnesi's gram-molar weight must be divide by 2 to get 96500 colombo equivalency (Mg2+).you must calculate how long you expect your sample to last.one amp is one colomb/second.one milliamp is one millicolomb/sec.one microamp is one microcolomb/sec

[jonfrommanahawkin1]

I'm having a hard time calculating how long the cell should last, I normally just try for as long as I can go and see when it will stop putting out current.
I found the Mol value
then divided
then multiplied by the constant but now I'm not sure where I should be going next
this is my work :

.70 g MG


Molar value
0.028800658300749998
÷2
0.0144003292
×
96500
1,389.631762975eq
  ÷24
=57.9013234573 days=?

I really just don't know
could you take a look and maybe show me how to do this equation?
Because 57 days does seem right as far as my experience goes with magnesium ribbon but the way I came to that numberseem very wrong shouldn't the value be in seconds so I should be multiply up to days and then the end value is 3,000 days and that can't be right?
but I ve never tried actually calculating it before

All the best
jon

Ps and if 3000 is right then "damn that's alot"

[profitis]

Hi jon it'l take precisely 11days of continuous 1milliamp current to destroy exactly 0.12gram magnesium so its best to use smaller weights in these type tests.the weight of the cathode is irrelevant ofcourse only the anode dissolves.

[jonfrommanahawkin1]

Thank you very much.
I'm graphing The voltage under a 1/8 wat 10 ohm resistor right now. My program only allows me to save up to five days of data. So I'm going to save it each day and record it. your more then welcome to review the data if you would like to. Much thanks
jon

#fingerscrossed

[profitis]

Exellent jon.what is your current at moment and what weight ribbon are you using.