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Marosz's Rdial Turbine ( SYMETRY IN PHYSICS NOT EXIST )

Started by tesla2, November 05, 2014, 02:34:05 PM

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tesla2

OK

mercury is more heavy than water

Water and Mercury are inside pipe diameter d and radius R


Oil ( green)  left / right is going  symetry
but boat will go  there where feel stronger radial  force

Fr mercury = Mmercury * V *V / R
Fr water = Mwater *V*V/R

Fr mercury = 13,59 Fr water

The same oil's capacity will go left/right


tesla2

MUCH MORE IMPORTANT IS OTHER PROBLEM

RADIAL FORCE ARE ABLE REDIRECT ENERGY
WITHOUT OPPOSITE TO MOTION REACTION

Directly we can redirect atoms inside material and move up material
electrons speed = 2170 km/s

Below link contain
1 explanation -  each mass m = satellite for N objects in universe
2 new force inside atom ( each electron = satellite for N objects in unierse)
3 Marosz's antygravitation Engine
4 Michelson Morley ( force edition how heavy is air Left/right )

5 I PROVED THAT NOT EXIST SYMETRY IN PHYSICS

6 I SHOWING NEW FALL LAW ( better than Gallileo ) 


http://maroszphysics.blogspot.com/

s3370389

Marosz,

I have attached a diagram. As far as I knew, the radial force (or centripetal force) is directed inward toward the
centrepoint of the circular path that the object is following. But you have your radial force directed outward
(a centrifugal force) why is that?

As far as I remember work is defined as W=Fd, where:
W = Work {Nm}
F = Force {N}
d = Distance {m}
I'm sure that you know this, but I want to make sure that I am speaking the same language as you. The mercury
and water must accelerate. However, the radial component can do no work as it is not in the direction of motion
(the radial force is acting perpendicular to the direction of the water and the mercury).

I don't think that the object at the link will move:
http://www.spacetimeandtheuniverse.com/space-time-universe/7885-maroszs-turbine-symetry-not-exist-real-world.html#post34907

Can you tell me what I am missing here?

s3370389


tesla2

water = many small mass m

F1+F2 + F3 .....+Fn = F

F1 = mV^2/R * cos@
F2
.......


http://2.bp.blogspot.com/-_SHx3z1xLbk/VFuMky3bIWI/AAAAAAAACDc/wGj2uK1L8XE/s1600/CIMG3383.JPG


1/4 pipe + 1/4 pipe = 1/2 pipe

My turbine = two springs and  1/2 water pipe + 1/2 mercury  pipe

Main idea is very simple
Each small mass m = each small pipe's peace



Please ask Your self
why people who repear water in home are giving foam on pipe in place where water is changing  direction

http://www.fachowyinstalator.pl/images/stories/porady_ogolne/zlaczki-i-ksztaltki-do-rur/zlaczki-i-ksztaltki_1.jpg