Lenz free generator

[EMJunkie]

Chris, to be more specific, the drag increases up to a certain point, then there is a dip, followed by a resumption of the increase.


This is with no electrical load being drawn, so it is not Lenz related. It must then be strictly a magnetic phenomenon.


Ron

Hi Ron, again consistant with my replication. The drag, normal to most all generators is Lenz's Law, as we know, but when the point is reached, where the Flux completes the Path of least reluctance, the Rotor Rides the Magnetic Field, because they are in Quadrature, and also confined to a small space.

   Chris Sykes
       hyiq.org

[EMJunkie]

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Registrations close on a date soon so be in to win!!!

   Chris Sykes
       hyiq.org

[lancaIV]

TESLA + Hector RT or TV : TESLA RTV   ,rotatory -translatory-linear, Peter Drucker "In search of Excellence" and other
                                                In search of the "ideal dynamo",
                                                           Linear Generator


Not to read   Tesla,studying and becoming
Not to read Hector,studying and becoming
Only one "thing" not :
To read the restaurant menu card,studying and please for becoming a steak ( become : english: to get anglo-saxonic:"to will be" or wise-men-(con)versa(tion)    aehh,pardon,I mean vice-versa   ,BS,I think this Feng-Shui does not becomes me )


Who invented the "ideal dynamo" and trying this the "real dynamo" ,in german "Selbstlaeufer" ?
Who invented the "auto-mobile starter" ,auto=Selbst=self, ?
https://www.google.pt/search?q=anlasser+funktion&client=opera&hs=X1O&sa=X&biw=1366&bih=668&tbm=isch&tbo=u&source=univ&ved=0ahUKEwiT-OS8vKfPAhWGWxQKHes0CJsQsAQIMA


Who invented the "ideal capacitor" and trying this the "real capacitor" ? 
Lord kelvin: comparing a spring (not a temporal saison period) with the capacitor behaviour !? Thermo-cryo-dynamic


                                   electro-static capacitor and/or magneto-static-capacitor ?
https://translate.google.de/translate?sl=de&tl=en&js=y&prev=_t&hl=de&ie=UTF-8&u=https%3A%2F%2Fworldwide.espacenet.com%2FpublicationDetails%2Fbiblio%3FDB%3DEPODOC%26II%3D5%26ND%3D3%26adjacent%3Dtrue%26locale%3Den_EP%26FT%3DD%26date%3D19790215%26CC%3DDE%26NR%3D2733719A1%26KC%3DA1&edit-text=
                                The Mukherjee "controle element/Steuerelement" ? Elementar~ important ?


The above calculation is only an approximate calculation, in the small losses, such as copper losses are not taken into account in the armature of the electrical equipment, energy losses for rotating the inertia around the machine with the required angular velocity and the like.The bill is intended to show that a large amount of energy can be obtained by only a fraction of the output power, but not some form of external energy is consumed.


By supplying the pure output energy of the inventive generator for the electrical device, the force generated in the system can be used to drive other, coupled with the wave machine. Since no fuel is consumed, all types of vehicles and machines with this generator can be operated.


                                                                   "eddy currents brake"and the "kinetic force"
                                                              https://en.wikipedia.org/wiki/Eddy_current_brake

[i_ron]

The answer to that is simple.
The already existing eddy currents are being converted to electrical power.
If Ron places a temp probe on the core of the generator,he will find that the temperature of the core will decrease when he draws a load from the generator.

Way to test for this.
1-place a temp probe on the core-or embed the probe into the core if he can.
2-let the DUT run at the best found RPM for 10-15 minutes-or until it reaches peak temperature.
3-once max core temperature is reached,place a load across the generator,and watch the core temperature.

You would think the temperature of the core/generator would go up,but it will go down,as the generator was already under load,and that load was the production of eddy current heating-waste heat.

Well,that is what i have found anyway.

Brad

Well Brad, I think we can scratch that one too.

Cool in the basement as the heating season hasn't started yet.

Starting temperature was 18 degrees C

After a 10 minute run...23 degrees C

After a 10 minute run under load...24 degrees C

The 50 ohm load resistor was at 72 degrees C after the 10 minute load run!

Ron


edit: the 23 C was fairly stable after 5 or 6 minutes. The scooter motor is not as efficient as the RV and was drawing 110 watts for the no load part of this test.

[i_ron]

Embarrassment time, dyslexia strikes again. The impressive second reading is an error on my part.

Correction for post #678

The millivolt numbers are correct in my notes, 11.6 mV under load and 10.3 mV no load. I was just dividing by two to get the amps and a very simple mistake occurred on the 11.6... I had written down 5.5 instead of 5.8 and subtracted 5.15 from it. What a difference that makes... from 8.575 watts to 16.25 watts! Sorry about that.


So corrected, the number two reading is 14.28 Watts out for a cost of 16,25 watts in


The best reading today is at 2800 RPM, 12.03 watts out for a cost of 12.5 watts in


The RV draw numbers are correct


Ron