Partnered Output Coils - Free Energy

[MarkE]

That is correct, but is that relevant for demonstrated Video , in the beginning. I think that was explained already.

reg

If we are talking about the video linked back in post 94 it is quite relevant.  EMJ made his measurements using AC coupling that he insisted must be used to obtain correct measurements.  That is completely wrong.  EMJ seems to be slowly coming around to acknowledging that.  In doing so, he has invalidated his prior measurements.

[TinselKoala]

The AC coupled voltage baseline is -1V and the pulses rise to +9V.  The DC coupled voltage baseline is -9.4V and the pulses rise to 0.6V.

Note that the AC-coupled signal is nicely area-averaged by the high-pass filter: you have 90 us x -1V, for -90 volt-microseconds _below_ the channel zero line, and 10 us x +9V, for 90 volt-microseconds _above_ the channel zero line, per 100us period.

But really, is this debate still going on? It's clear to everyone that EMJ was wrong in the beginning about the use of AC vs. DC channel input coupling "after all those wasted years", and the rest of his talk about this topic is just trying to justify his error and cover it up. I laugh when I read his statements about contacting scope manufacturers... who, each and every one of them, will definitely _not_ agree with him! Every Digital Oscilloscope that I have ever seen _defaults_ to DC coupled input channels when reset, in spite of the fact that most signals that anyone will measure on a scope are "AC" of one kind or another. And _every_ oscilloscope, analog or digital, accomplishes the AC-coupling task in the same manner: They put a _capacitor_ in series with the probe input! Before the attenuator/preamps, even! So the absolute voltage values of the input signal are _altered_ and only peak-to-peak values are reliable, and this will be true in the general case. Only in the very specific case of an absolutely +/- symmetrical, 50 percent duty cycle, sine or square or other symmetrical wave will there be no difference in the AC and DC coupled traces.  Because, as MarkE's example shows, the AC-coupling not only "removes DC offset", but it also area-averages the signal around the channel's zero voltage reference level.

[a.king21]

Whilst this debate rages something else is happening:


http://overunity.com/15764/r-walker-selfsustaining-free-energy-bike-from-mexico/msg450482/#msg450482


Looks like this kid's succeeded in converting var into real power.
Better get the suppressors working fast on this one.

[MarkE]

Note that the AC-coupled signal is nicely area-averaged by the high-pass filter: you have 90 us x -1V, for -90 volt-microseconds _below_ the channel zero line, and 10 us x +9V, for 90 volt-microseconds _above_ the channel zero line, per 100us period.

But really, is this debate still going on? It's clear to everyone that EMJ was wrong in the beginning about the use of AC vs. DC channel input coupling "after all those wasted years", and the rest of his talk about this topic is just trying to justify his error and cover it up. I laugh when I read his statements about contacting scope manufacturers... who, each and every one of them, will definitely _not_ agree with him! Every Digital Oscilloscope that I have ever seen _defaults_ to DC coupled input channels when reset, in spite of the fact that most signals that anyone will measure on a scope are "AC" of one kind or another. And _every_ oscilloscope, analog or digital, accomplishes the AC-coupling task in the same manner: They put a _capacitor_ in series with the probe input! Before the attenuator/preamps, even! So the absolute voltage values of the input signal are _altered_ and only peak-to-peak values are reliable, and this will be true in the general case. Only in the very specific case of an absolutely +/- symmetrical, 50 percent duty cycle, sine or square or other symmetrical wave will there be no difference in the AC and DC coupled traces.  Because, as MarkE's example shows, the AC-coupling not only "removes DC offset", but it also area-averages the signal around the channel's zero voltage reference level.

In the past day, EMJ has acknowledged some of the conditions that are required in order for AC coupling to indicate accurately.  He has failed to show any condition where AC coupling is required to indicate accurately as he first insisted was true for all AC signals.  So, we have some progress.  He still does not seem to get the point that the high pass filter distorts signals from several times the cut-off frequency down to DC.

As picowatt reminds us and was discussed at length, EMJ's even bigger problems come from his choice of ground reference to his scope.

[MarkE]

The circuit presented is a simple DC clamp.  This sort of circuit is used many places.  The old analog TV sets used this sort of circuit to recover synchronization pulses.  If you flip the diode upside down, the AC coupled waveform will have almost but not quite the same levels as the DC coupled waveform.