Partnered Output Coils - Free Energy

[minnie]

  I really miss Mark, if I was struggling with a concept he could always set me straight
via a PM.
     We've had a hopeless summer sunwise but the last couple of weeks have been great,
plenty to keep the car running!
  I see Toyota has gone for hydrogen-under the right circumstances it can go for a
wizard bang.
    Who would have thought a poxy transformer could have been so complicated?
             John.

[poynt99]

When i asked-Quote: So,in the video below,are you saying that the current flowing through the secondary coil is being produced by an E field only?,as the magnetic field/magnetic flux is contained within the core.
And you answered,Quote:-yes

Correct. And as indicated in your question, that E field arises from a B field (within the core), which I have stated many times. To reiterate; emf is induced by an E field, which itself is induced by a B field. In the reactive near field, that's the end of the game.

So now some time for testing. In the video- https://www.youtube.com/watch?v=x-EuPGl8JjE
do you believe in this instant that the secondary would be energized by a near field or far field?.

Unless he is operating at relatively high frequencies (>150MHz or so), that transformer is operating in the near field.

Second(to help me with my testing and understanding)in regards to a setup like that of the above video-,if it is the current flowing through the primary that causes the E field that is inducing the EMF and current flow through the secondary,should not the secondaries EMF be in phase with the current flow of the primary,and not the voltage across the primary?.

Lenz's law and that Maxwell equation I posted above tells us what polarity the induced emf will be. You can also use the right hand rule if you know the direction of the flux.

If i raise the frequency on the primary so as we get a phase shift between the voltage(leading)and the current(trailing),should not the secondaries EMF be in phase with the current of the primary(as it is the current that produces the E field),and not the voltage across the primary?.

Intuitively, that would be the case. However, it takes energy to polarize the core, not current or voltage alone, so just like we do with the scope to compute power by multiplying the two then averaging, we should have the same effect with the core. Try it and let us know. You may find that the two voltages track, and the two currents track.

[tinman]

Correct. And as indicated in your question, that E field arises from a B field (within the core), which I have stated many times. To reiterate; emf is induced by an E field, which itself is induced by a B field. In the reactive near field, that's the end of the game.
Unless he is operating at relatively high frequencies (>150MHz or so), that transformer is operating in the near field.
Lenz's law and that Maxwell equation I posted above tells us what polarity the induced emf will be. You can also use the right hand rule if you know the direction of the flux.
Intuitively, that would be the case. However, it takes energy to polarize the core, not current or voltage alone, so just like we do with the scope to compute power by multiplying the two then averaging, we should have the same effect with the core. Try it and let us know. You may find that the two voltages track, and the two currents track.

Below is a picture of my setup,and associated components.

My P/in is from a transformer running from main's,so the frequency is 50hz.
The voltage and current are slightly out of phase on the primary(voltage leading of course),but both are in phase on the secondary. The secondaries voltage and current phase are in phase with the voltage across the primary coil,but lead the current phase on the primary coil 

The scope shot in the background shows the current trace on both the primary(blue trace),and the current on the secondary(yellow trace). As you can see,even though the wave form is distorted due to the transformer being unable to supply enough power,that the current on the secondary is leading the current on the primary-some how.

[poynt99]

If you could try to achieve relatively clean sine waves, then you'll have a better insight.

With that much distortion and the harmonics involved, it's difficult to say exactly what is happening with the phases.

[MileHigh]

The scope shot in the background shows the current trace on both the primary(blue trace),and the current on the secondary(yellow trace). As you can see,even though the wave form is distorted due to the transformer being unable to supply enough power,that the current on the secondary is leading the current on the primary-some how.

This is not necessarily the case if you did not do a full check into this issue.  Who says that when you see a positive current pulse on the primary that with your existing setup and configuration it will give you a positive current pulse on the secondary?  Are you sure that you are not just assuming this?  Maybe it gives you a negative pulse and if that's the case then current in the secondary is lagging the current in the primary.

Look at the possibilities that you have to consider:  1) What is the dot convention for your transformer setup?  2) If your scope is isolated then you have two ways (a.k.a. polarities) to connect the scope probe on the primary side. 3) There are two ways to connect your scope probe (a.k.a. polarities) on the secondary side.  4) It's unlikely, but your scope channel A may be inverted.  5) It's unlikely, but your scope channel B may be inverted.  6) It's unlikely, but for some reason the phase delay between input and output may be 180 degrees or more.

Have you checked all of this, paying particular attention to your dot convention for your transformer setup and the scope probe probe connection polarities?

How about a simple test without even having to check all of this?  Suppose that you disconnect the mains.  Then you take a 9-volt battery and just make a quick connection to the neutral and hot inputs on your transformer primary, of course with the battery ground on neutral and the battery +9V on hot.  Look at your scope display.  You should see the positive jump on the scope channel connected to the primary.  What did you see on the channel connected to the secondary, a positive jump or a negative jump?

If you did that test I suspect that you would see a negative jump.