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Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

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0 Members and 172 Guests are viewing this topic.

forest

Mags


I think there is one thing to consider about your pdf. If core is ring and you put a additional path of high permeability into a center of it with a very slight air gap and you drive it with sinewave power at very low frequency then I imagine the flux lines in air are impossible to reach the opposite site of ring core.

EMJunkie

Quote from: Magluvin on July 25, 2016, 02:23:19 AM

Hmm. I get all that.  What I want to know is if you believe in flux cutting in order to induce current in a secondary conductor, or do you believe that it is an E field that produces current in the secondary conductor.   

The pdf below explains my argument. Its not a long read.

Mags



Hey Mags, yes of Course, EMF = Bvl, for sure Flux Cutting would induce an EMF, but the efficency would be poor, in the particular configuration.

Yes, have seen the work of Mr Distinti B.S. E.E. - They seriously need to change the B.S. bit in Science!!!

It is easy enough to throw a few coils on a core and test, I did many years back, it was very poor efficency! Can you tell me why it would be poor efficency?


   Chris Sykes
       hyiq.org


P.S: I am coming from the Transformer Point of View. Like was shown in the pdf you posted. This is a generalisation and is how this question might be viewed as a Industry point of view, but in practice, this is not always the case, so dont let my answer change your mind, merely look at my posts as a generalisation as not all Configurations are true of the same problems. 1.6 Tesla is a common B Field Maximum in some Core Materials. Please remember, Magnetic Flux will always try to take the Shortest Path with the least Reluctance...


EMJunkie

Quote from: EMJunkie on July 24, 2016, 08:38:38 PM


Power is the Product of Voltage times Current, averaged over time and this power is called the Mean, or Average Power.

How does this work, and what does area have to do with it?

To Integrate the Wave Forms means to take as many small Rectangles under each of the Wave Form's, and get the value of this very small Rectangle, it is really good to watch this video: What Is an Integral? - Thus Integrating the Wave Forms gives us a Value over time of the Power. Thats why Area of the Rectangles are important.

The Mean or Average Power over Time, which is in its own right, Watts, Energy over Time, or Joules Per-Second.

This is done for Current (I) and at the same time for Voltage (V) and each Rectangle is thus the Product, Voltage (V) * Current (I) over Time = Watts.

As an example, at the Peaks shown above, on the Yellow Lines, each Yellow Line could represent a small rectangle. This Area was calculated and the Figures for an Instantaneous value of Power:

   Peak Power (Real) :
       Instantaneous: V * I = 2.37 * 0.0225 = 0.053325

   Peak Power (Negative) :
       Instantaneous: V * I = 11.75 * 0.075 = 0.88125


So, the more area the more the Average or Mean Power will be. Either Input or Output... No one has pointed out any mistakes, and I have made some, to see if anyone was paying attention...

EG: Voltage should have been: -11.75 and not 11.75 also, the Phase angle was not 90 on the input, but in fact closer to 82 Degrees. Its not important any way as this was irrelevant.

   Peak Power (Negative) :
       Instantaneous: V * I = -11.75 * 0.075 = -0.88125

Below, the Red Boxes are Current, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive, the Blue Boxes are Voltage, to be Integrated from the Zero Graticle Line to the Wave Peak, Negative or Positive - The Product, is Voltage times Current, and these Values are averaged over time.

We are going to have to be smart and cross all our t's and dot all our i's if we are going to get anywhere with this. Once a grasp is obtained, it gets so much easier.


   Chris Sykes
       hyiq.org


P.S: Just maybe, the assumed knowledge of, or lack of, the Scope, was slightly under appreciated...

P.P.S: I should be Clear, this is Input Only Analysis, on a LC Tank Circuit with Permanent Magnets added to the System, no Output has been looked at yet.


It should now be obvious to all reading, that did not already know, that the Power Into/out of a Circuit can be Positive (+) or Negative (-). For example:

   Power (P) = -Voltage (V) * Current (I) = - P

or

   Power (P) = Voltage (V) * -Current (I) = - P

but, the Positive Power into a Circuit will always be Positive:

   Power (P) = Voltage (V) * Current (I) = P


I will let you think on this for a bit, as it does have consequences...

   Chris Sykes
       hyiq.org


Magluvin

Hey Chris

Do you have a link to that transformer depiction?

Mags