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Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

Previous topic - Next topic

0 Members and 174 Guests are viewing this topic.

tinman

Quote from: hoptoad on May 26, 2015, 05:54:42 AM
Good question indeed, that's why I'm finding your experimental toroid arrangement so fascinating.
The greatest amount of power I have ever off loaded from a collapsing field kickback is approximately 25% of the original input power.

Cheers
That is correct hoptoad.
MH him self once said you would be doing good to recover around 35% of the electrical energy in the inductive kickback. I am yet to see any here confirm as i have that they to can get 100% back during the off state that they get from the secondary during the on state.

A lot of people are missing what is actually going on here-even the best of them.
L1 switches on,and induces a current flow in (what we will call L2)the internal coil. The efficiency here is 75 to 77% conversion/transfer to L2. This means i get back just 75% of the P/in during this on period through L2. What people are missing here is that i then get back 100% of what was produced in L2 during the on time,during the off time.

This is the reason for all these test,and check's,as i need to know where the full 100% during the off time is coming from. We have eliminated the scope,and we know there is nothing wrong with the transformer as a whole-->and im preaty sure the SG will not be delivering that much extra power to the system,as we are using fet's.. At very best,the FG can only deliver 60mW through that 100 ohm resistor. But the gate on the fets(unlike a transistor) work on voltage with very little current required.

Red_Sunset

EMJUNKIE,

You can post whatever you like so long you do not say the forbidden word "OVERUNITY"
That would be copyright infringement !

If you really want to, no matter what,  the least you can do is bring with a witness who can vouch for you.

Red

tinman

Quote from: forest on May 26, 2015, 06:01:49 AM
Every transformer is always 200% efficient unless we construct them to generate hv spike instead of a copy of original energy put into. This knowledge dissapeared somehow around year 1900, with just a few later inventors stepped on this acccidentally.So we had press reports abour C.Earl Amman, Hubbard , Hendershot and few others between 1918 and 1939 .
The copy is the actual output and I have theory that it is taken from external force field - Earth magnetosphere. The original energy is always in primary and dissipated as heat or radio waves or HV spike.
Well something is going on here forest,but most here have totally missed what has to take place in order to get the results im getting. Some say that the inductance is better in the center toroid core than the steel putty. No argument there,but they forget the fact that the center core(ferrite)is about 10mm away from the outer windings. So the field still has to travel through the steel putty to get to the center core that has better inductive performance. Then there is the coil that is wound right next to the primary around the outside of the core-which dosnt put out even half the power of the inner windings during the on time of L1-this i showed in the last video.

So the steel putty is a poor inductor-fine,so how is it that the coupling is better with windings 10mm away to those that are wound right next to(and over)L1?.
The reason is that the magnetic field within the center of the toroid is far stronger,and continues to exist for a far greater period of time to that of the field around the out side of the toroid core when L1 switches off.

MarkE

Quote from: tinman on May 26, 2015, 06:10:53 AM
That is correct hoptoad.
MH him self once said you would be doing good to recover around 35% of the electrical energy in the inductive kickback. I am yet to see any here confirm as i have that they to can get 100% back during the off state that they get from the secondary during the on state.

A lot of people are missing what is actually going on here-even the best of them.
L1 switches on,and induces a current flow in (what we will call L2)the internal coil. The efficiency here is 75 to 77% conversion/transfer to L2. This means i get back just 75% of the P/in during this on period through L2. What people are missing here is that i then get back 100% of what was produced in L2 during the on time,during the off time.

This is the reason for all these test,and check's,as i need to know where the full 100% during the off time is coming from. We have eliminated the scope,and we know there is nothing wrong with the transformer as a whole-->and im preaty sure the SG will not be delivering that much extra power to the system,as we are using fet's.. At very best,the FG can only deliver 60mW through that 100 ohm resistor. But the gate on the fets(unlike a transistor) work on voltage with very little current required.
Depending on the voltage and current levels involved better than 90% BEMF energy reclamation is performed by off the shelf power supplies and motor drives today.

Any appearance of extra energy is likely due to the layout of the circuit and the scope probe connections.  Oscilloscope probes, particularly passive probes like you are using load, IE become part of the circuit that they measure.  Whenever one connects to signals that turn on and off quickly it is very easy to end up with quite a bit of measurement error.  Steven Jones went down that path and thought he had 8X OU where he had none.  One thing that you can do that will clean up some of the junk that the 6" probe ground clips introduce is to go buy some 100 Ohm ( the value can be anything from 75 Ohms to 150 Ohms ) and cut one lead pretty short and solder that side to the place you would normally clip the probe hook.  Instead clip the probe close to the resistor body on the free end.  At the price of slowing down the oscilloscope rise time, it will greatly limit the ringing caused by the inductance loop between the probe tip and the ground clip acting in parallel with the capacitance of the probe cable back to the oscilloscope. 

The other thing that can eat your lunch is inductance in the current sense resistor.  You want the L/R time constant of your current sense to be less than 1/10th the rise time of your signals.  If your signal rises and falls in 100ns, and you are using 1 Ohm resistors in parallel, then your maximum inductance is about 10nH per resistor.  Garden variety 1/4 film resistors are more like 100nH or more, so that could be an issue.  Also any lead length from the resistor body to either the scope probe ground clip or probe hook adds to that inductance.  TK has some videos showing the distortion regular cement resistors introduce versus a good quality "non-inductive" current sense resistor.

TinselKoala

Quote from: tinman on May 26, 2015, 04:50:41 AM
Looks like the off time current flows to about the mid way point between pulses,and then hits that bump at the 0 volt line-is this correct TK,as it is hard to make out the horizontal lines in that pic.
Yes, that's right.

Here's another shot I just did. This is with a small pot-core that was donated to the lab by a friendly researcher. I wound 10 turns of #22 magnet wire for a "primary" then 30 turns of #27 magnet wire for a "secondary" on the little bobbin, then assembled the pot-core around it and clamped it together with a #4-40 screw and nut. I'm using a 33 ohm load made of three carbon 100ohm resistors in parallel. The shot is taken across the load.
The FG drive is at 5 percent ON duty cycle and -2, +10 volts.

I don't usually like to show clipped waveforms but here I'm doing it so that the negative voltage shows up well. The true peaks are at 29 volts positive.