Open Systems

[tinman]

This is only true for an adiabatic process, where no thermal energy enters or leaves the system.

Push the piston in and it heats up. Work is converted to heat. The temperature in the system is raised and P1V1 != P2V2.

If you then held the volume constant and allow all the extra heat that was converted from work to transfer back to the environment THEN  P1V1 == P2V2 and the internal energy will also be same as the starting condition.

I don't know why you don't seem to be able to grasp such a simple concept, but by refusing to accept it is shows any other conclusions you have come to about your system to be false.

Do you have a mind of your own? Or do you just repeat what others have already said-and whats with all the googlegasms you keep having?.

[tinman]

So why don't perform this experiment. If you do you'll realise you have been mistaken all along.

What you will find is that when compressed the temperature of the gas rises. The rise in proportional to the amount of work done to compress it. The WORK is converted to HEAT...

When it decompresses the HEAT is converted to WORK. It is as simple as that.

What happens in reality of course is that we don't have a perfectly insulated cylinder and heat losses occur. However these losses
don't ever add to the efficiency of the conversion process. Likewise the fact that our working fluid is not a perfect gas.

Nope-the heat already exist, the work done is to reduce the volume of the gas, and thus concentrate the heat . No work is done to create heat.
And you think I havnt done any experimental work toward this? Lol..

[MarkE]

Nope-the heat already exist, the work done is to reduce the volume of the gas, and thus concentrate the heat . No work is done to create heat.
And you think I havnt done any experimental work toward this? Lol..

You really need to do some studying.

[tinman]

You really need to do some studying.

You really need to get out of the past.-200 year old calculations based on a gas that dosnt exist-thats the ticket

Now in regards to my setup, what energy do you think Elvis took with him when he left the building?

[LibreEnergia]

Nope-the heat already exist, the work done is to reduce the volume of the gas, and thus concentrate the heat . No work is done to create heat.
And you think I havnt done any experimental work toward this? Lol..

Absolute BS.

When you push on the cylinder the gas is moved, does it not?

So what is heat? It is the simply the sum of all the kinetic energy of the molecules. Since we 'moved' the molecules using an external force the kinetic energy of the molecules must have increased. Therefore the heat content of the gas rises. It is NOT  due to 'existing heat' somehow being concentrated.

If not, where did the work we expended go to? Free space? the moon?, exited via a black hole?  The only place it goes is into the heat content of the gas.