How Rosch probably faked their 5 KWatt KPP AuKW

[markdansie]

Soo
Is this true ??
there was a personal invitation to witness the disassembly ?

I don't really follow peswiki hard to separate facts at times .. we even have anonymous clowns coming here bragging about making up stories and playing games with peoples lives over there ??

An invitation??

No point in travelling across Germany given there were several days where things could have been renovated, changed and all evidence erased.
This is a very bold scam
Kind egards
Mark

[magpwr]

hi everyone,

I think i have come up with a super easy way to detect if it's fake or for real merely by looking at the device creator intention.

I think this quick 1-cent worth of suggestion of mine as shown below is gonna to be idiot proof or preventing anyone from becoming idiots in future-

Any free-energy device creator is looking for investor.It's fake right away.

If any free-energy device creator is intending to sell any assembled working device be it just 1 or more.This is likely the real deal.

-----------------------------

The only free-energy sales i've heard off is Don-Smith via video and Akula device sales to China buyers via video.
Although Tariel case was a sad one he gonna take it to his grave since he don't want the world to own this technology base on old translated video.

[Pirate88179]

No point in travelling across Germany given there were several days where things could have been renovated, changed and all evidence erased.
This is a very bold scam
Kind egards
Mark

Mark:

For whatever it might be worth, I agree.

Bill

[TinselKoala]

@magpwr: While I think you are on the right track, your system isn't quite perfect.

For example, I will gladly sell the prototype Cheese Power demonstrator, and the complete secret of Cheese Power, for the trifling sum of 998 dollars US, subject to only two conditions: A signed NDA that says the buyer will not disclose the secret for two years after the purchase date, and the funds are to be remitted to me in _cash_ (Western Union wire transfer or similar).

I'll even offer a moneyback guarantee: if you are not satisfied that the device is exactly as I have represented it, you may return it for a full refund... as long as it is in working condition when returned. The NDA still will hold for the full two years of course.

Note that I am offering for sale 1 prototype of the Cheese Power demonstrator, along with a suitable chunk of Cheese, and all rights (except public disclosure for 2 years) that go along with it, like commercialization, patent rights, trademarks, etc. You buy it, it's yours to do with as you wish.

http://www.youtube.com/watch?v=Frp03muquAo

[conradelektro]

Why the calculation in

http://revolution-green.com/rosch-smoking-guns-and-the-scientific-explanation/ or

http://pesn.com/2015/05/13/9602617_scientific-explanation-for-Rosch-KPP-buoyancy-system/

is wrong:

The first power calculation in the article is:

== Formula 1 ====   Thus, we get: N = 9.81 x 2 x Q x 0.5 x H x 3 = 9.81 x Q x H x n ====
Further down one calculates:
== Formula 2 === N = 9.81 x 0.167 m3/sec x 2 m x 5 x 0,9 = 14.7 kW  =====
There is the error of putting "2 m" in again, because 2 was cancelled by 2 * 0.5 in Formula 1.
Therefore the corrected Formula 2 is:
== Formula 2 corrected === N = 9.81 x 0.167 m3/sec  x 5 x 0,9 = 7.35 kW  =====
But there is a further error in "Formula 2 corrected", which is the factor 5, because of  "5 working wheels above each other".
If there are 5 wheels above each other the water rises from one wheel to the other only 0.4 meters and not each time 2 meters. Therefore we can calculate with one wheel a height H of 2 meters, or for 5 wheels a height of H 0.4 meters each. We can calculate with one wheel with H = 2, or we can calculate with 5 wheels with a H = 0.4. So, either H = 2 or H = 0.4 x 5, which is the same.
Finally we end up with a correct "final Formula 2":
== final Formula 2 === N = 9.81 x 0.167 m3/sec  x 0,9 = 1.47 kW  =====
In addition we have to factor in a bigger loss than 0.9 because of the very optimistic height H = 2. If the water rises 2 meter it encounters friction at the wheel and some water is lost because it runs through gaps.
Further there will be losses in the gear connecting the wheel with a dynamo and the losses in the dynamo itself.
Therefore we will get much less than 1.47 KW.
Please note: I have not criticised the calculation itself (although one should do that), I only corrected obvious errors.


Criticism of "Formula 1":
The formula stems from water turbines http://en.wikipedia.org/wiki/Water_turbine#Power and assumes that water is falling down through the turbine. But one is not allowed to assume the same efficiency if "bubbly water (water air mixture with 50% air) rises through a turbine" rather than "smooth water is falling through a turbine". Much higher losses by friction of "bubbly water rising" in contrast to "smooth water falling" have to be assumed. And if things happen slowly (as is necessary in the "bubbly water rising case"), the formula is overly optimistic, because the formula only works with rather fast moving water.

Greetings, Conrad