MY PATENTED DEVICE DOES NOT WORK!

[mr2]

This was fun.

People who knows what they are talking about.

Have you tested it live? Nope, you have formulas!
Hence the truth.. Stupid...

https://www.youtube.com/watch?v=54Bj_V0acAo
This explains the theory. But sorry, in Norwegian..

1F, 11V. 1000uF capacitor as drive-capacitor.
First tests: 11V, each pulse 1000uF: about 660 pulses.

With my change of same components, but charging the capacitor via the electromagnet;
The time charging the capacitor is used to run the motor. The loss of time is adjusted to the time to charge and discharge the capacitor.
980 pulses and a much higher voltage and therefore highter restvalue of energy.

Same energy when starting, same energy per pulse.. and a closed circuit..

They say: Where did the half of the energy go? And all proof is math. But electrons have no other way to go, but via copper wires.

Yet another test comparing a "state of the art" motor from any shop:
https://www.youtube.com/watch?v=NYfE_qjf4jo

[mr2]

... AND it works on any motor the method is connected to..

So; if it have been explained as "radiation" or all other stupid explanations, it would not work, since half of the energy is wasted when charging and discharge a capacitor.
It is prooved by several tests; both homemade motor, and commercial motors that it actually work..

[mr2]

Maxwell's equations tell us that any rate of change of current through a circuit radiates E/M energy.  Experiments go back to the 1800's.  Everyday thousands of engineers conduct these experiments in EMC labs doing what they need to to reduce the radiation to acceptable levels.

Fun... Protecting the statements by talking about old experiments with components from that time.. And have the knowledge just by reading it..

[mr2]

There is no EM losses or any other losses-->the !/2 charge that seems to be missing is still in the cap. The electrons dont just go zipping of into the sky,or get radiated as heat-the electron flow is what creates the heat. The higher the restriction to this flow,the more heat is generated-electrical flow friction.

When you charge a cap or a battery,your charging source is nothing more than a pump. This pump is what pumps the electrons from the positive plate,back to the negative plate. When there is no voltage across the cap,you havnt used the charge,you have simply provided a path for the electrons to flow to the positive plate. This is the very same as the water in the two tanks wanting to reach an equilibrium-->the charge is still in the caps. The problem is,there is now no potential difference between the two charged plates.

You have understood it!

When charging a capacitor you have only the loss of time, a time represented by R.
If you then have a motor running at 1000 RPM, there is x cm between the magnets, you have a Y ms time between the magnets.
You then have to calculate the size of capacitor that have at least 87% the time of charge and discharge.

Then you have like a "AC signal" on the oscilloscope because of LC.

[Void]

mr2, what sort of overall efficiency have you measured?
All the best...