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Overunity Machines Forum



Accurate Measurements on pulsed system's harder than you think.

Started by tinman, December 09, 2015, 07:59:10 AM

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0 Members and 7 Guests are viewing this topic.

EMJunkie

Quote from: TinselKoala on December 11, 2015, 05:45:06 AM
No, both channel baselines are one division below centerline. The Blue channel marker is overlaying the Yellow channel marker so you can't see it, and the yellow marker you do see is the Trigger level indicator, indicating Trigger on CH1 (because it is yellow) and at approx. 2 Volts above the baseline,which puts it just a hair below the screen centerline marker. (See the exact trigger level on the bottom right of the screenshot I've posted.)

TK, Ok I will take your word for it but certainly looks deceiving. Thinking about this, it is correct and Brads Mean Value is right on Ch1.

Still, this still means we only have a Potential Voltage Difference of 3.374 Volts as opposed to the 8 Volts with the Cap disconnected. Being that Power is V x I when in phase, we can see a clear difference in total power through the Components in question.

8 x 0.096 = 0.768
3.374 x 0.144 = 0.485856

   Chris Sykes
       hyiq.org

EMJunkie

Quote from: tinman on December 11, 2015, 05:57:08 AM
No-the yellow marker for channel 1 is being hidden by the blue marker of channel 2. The yellow marker you see at the base line is the trigger marker,and it is yellow because i am triggering on channel 1. If i was triggering on channel 2,then that marker on the base line would be blue.


Brad


Yes, certainly not easy to make out from the video. Honest mistake all sorted now.

    Chris Sykes
       hyiq.org

tinman

Quote from: TinselKoala on December 11, 2015, 05:20:16 AM
I'm not sure we are actually measuring any true power values yet.

In your original circuit, and my no-Bedini modification, the CH1 voltage drop across the bulb doesn't represent the input voltage to the circuit. The CH2 current is the input current, certainly, and actually the CH1 voltage drop across the bulb must also represent the input current and because of that we could calculate the resistance of the bulb.

That is, if the input current from the one-ohm CVR is, say, 94 mA (because we have  94 mV drop across 1 ohm), and we have 3.4 Vdrop across the bulb, then since both are obviously carrying the same current, we have R = V/I  so Rbulb= 3.4V/0.094 A = 36.2 Ohms. 

So maybe now we can get the power dissipation in the bulb at that current, since Watts=I2R. So we have for example W = 36.2 x (0.098)2 = 0.347 Watt being dissipated in the bulb. This is with capacitor connected in my circuit.

With cap disconnected and using the "average" values and going through the same calculations, we have average I = 62 mA and average Vdrop = 2.06 V, so the bulb's average resistance is V/I or 2.06/0.062 = 33.2 Ohms. So the average power dissipated in the bulb is 33.2 x (0.062)2 = 0.127 Watt.

What is the conclusion we can draw from this, since the bulb is obviously brighter when the cap is disconnected? Perhaps:  Using the "average" values in the way we have been doing is not correct in the case of pulses through a bulb; OR perhaps: Our assumption about the relationship between the bulb's brightness and the "average" power _in the pulses_ is not correct. Or both.

Or maybe my math is just totally screwed.

have eliminated the inductor entirely, along with the long leads I used to connect it, and I've simply placed a 34 Ohm resistor directly on my little breadboard between the bulb and the mosfet Drain, and the effect still happens just as before. There is less spikeyness when the cap is connected but the bulb dims while the "average" current through it goes up, just as before.

QuoteAs far as the inductor goes... it is not necessary to produce the effect.

;) . Indeed TK,the inductor is not needed--just a pulsed system-as the thread title says.

A little info to digest.
To obtain the 22mV across the solar panel resistor(as shown in my last video),using a DC current,i need 186mA @ 5.1v to achieve the 22mV across the solar panel resistor. This is 948mW.

@ TK
Can you place a DMM amp meter in series with the CVR and bulb,and see if that gives you the same value your CVR is giving you in current amount.
Cheers

Brad

tinman

Quote from: EMJunkie on December 11, 2015, 06:13:57 AM

Yes, certainly not easy to make out from the video. Honest mistake all sorted now.

    Chris Sykes
       hyiq.org

You must have a small or bad monitor EMJ,as it looks clear to me.
Hope this shows how things really are.

Brad

EMJunkie

Quote from: tinman on December 11, 2015, 06:24:00 AM
You must have a small or bad monitor EMJ,as it looks clear to me.
Hope this shows how things really are.

Brad

Hahaha 1080P compared to 240??? Max in the youtube settings is 240P

Maybe you just have better eyes than me?  :D

    Chris Sykes
       hyiq.org