Accurate Measurements on pulsed system's harder than you think.

[EMJunkie]

What is X and what is Y...

This is a bit on the cryptic side...

   Chris Sykes
       hyiq.org

P.S: Feel free to prove me wrong if you like! Your scope shots tell the story. The Applied Voltage Potential across the components is clearly visible. Also please explain what the differences are in the circuit so we can more precisely see what it is that you said I have wrong.

[tinman]

What is X and what is Y...

This is a bit on the cryptic side...

   Chris Sykes
       hyiq.org

P.S: Feel free to prove me wrong if you like! Your scope shots tell the story. The Applied Voltage Potential across the components is clearly visible. Also please explain what the differences are in the circuit so we can more precisely see what it is that you said I have wrong.

X/Y is volt's. It dose not matter what that voltage value is,as we are dealing with an incandescent bulb-a resistor that changes value with an increase in temperature.
Once again,how do you increase the temperature of the bulb?. Like i said,the bulb is doing the opposite to what it should be doing. How do you increase the dissipated power of a resistor ?.
How many times have you seen people using small/low value CVR's to measure high powered system's,and assume that the resistor is ok,as the total average power is below the rated value of that resistor.

Now,put together the outcome and dissipated power of the bulb with my last video(the video showing the experiment with and without the rotor full of magnets.


Brad.

[EMJunkie]

X/Y is volt's. It dose not matter what that voltage value is,as we are dealing with an incandescent bulb-a resistor that changes value with an increase in temperature.
Once again,how do you increase the temperature of the bulb?. Like i said,the bulb is doing the opposite to what it should be doing. How do you increase the dissipated power of a resistor ?.
How many times have you seen people using small/low value CVR's to measure high powered system's,and assume that the resistor is ok,as the total average power is below the rated value of that resistor.

Now,put together the outcome and dissipated power of the bulb with my last video(the video showing the experiment with and without the rotor full of magnets.


Brad.

@Brad - I completely disagree with this statement!

An Applied Voltage Across a 1 Ohm Resistor of 1 Volt gives 1 Ampere of Current through the Resistor. (1 Watt of Power)

An Applied Voltage Across a 2 Ohm Resistor of 1 Volt gives 0.5 Ampere of Current through the Resistor. (0.5 Watts of Power)

An Applied Voltage Across a 100 Ohm Resistor of 1 Volt gives 0.01 Ampere of Current through the Resistor. (0.01 Watts of Power)

Power = Volts x Amps if Phase Angle = 0. Voltage is a critical part of the Equation!

The Voltage Applied across a Circuit Element is critical and has to be taken into account!!! Look at a Voltage Divider for example! By changing the Circuit Impedance after any component will change the Power that flows through the component. It cant be assumed that it will not, it doesn't work that way!

Introducing the Capacitor did the same thing. Circuit Impedance changed! Voltage across the components in question went down but the Current went up. Total Power through these Components went down! (Thus the Dimmer Bulb) Not Up!

   Chris Sykes
       hyiq.org

[EMJunkie]

Re: Heating and Current Shunts, they are relative.

Rated for maximum accuracy at the least Temperature drift.

See Images:

   Chris Sykes
       hyiq.org

[tinman]

@Brad - I completely disagree with this statement!

An Applied Voltage Across a 1 Ohm Resistor of 1 Volt gives 1 Ampere of Current through the Resistor. (1 Watt of Power)

An Applied Voltage Across a 2 Ohm Resistor of 1 Volt gives 0.5 Ampere of Current through the Resistor. (0.5 Watts of Power)

An Applied Voltage Across a 100 Ohm Resistor of 1 Volt gives 0.01 Ampere of Current through the Resistor. (0.01 Watts of Power)

The Voltage Applied across a Circuit Element is critical and has to be taken into account!!! Look at a Voltage Divider for example! By changing the Circuit Impedance after any component will change the Power that flows through the component. It cant be assumed that it will not, it doesn't work that way!

Power is Volts x Amps if there is no Phase Angle. Voltage is a critical part of the Equation!

Introducing the Capacitor did the same thing. Circuit Impedance changed! Voltage across the components in question went down but the Current went up. Total Power through these Components went down! (Thus the Dimmer Bulb) Not Up!

   Chris Sykes
       hyiq.org

Can you raise or lower the voltage across that resistor without raising the current flowing through it?.
Can you increase the temperature of the bulb element without increasing the total current flowing through it? Current is what increases the element temperature,and an increase of temperature means an increase in resistance,but the increase in current must happen before the increase of resistance can exist. We decreased the average current flowing through the bulb,but increased the temperature-thus resulting in an increase of resistance-->but to what extent. Look at the scope shot's again,dose the current trace not tell you that the resistance is rather constant during the on time?-->in fact,is it not opposite to the shape of the trace curve that should exist if the resistance was increasing during that current pulse?. Draw a current trace of a pulse of current that has an increasing resistance during that pulse,and then compare that with the current trace in the scope shot. And remember,we are at low frequencies here.


Brad