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Overunity Machines Forum



Resonance Circuits and Resonance Systems

Started by hartiberlin, March 15, 2016, 03:27:11 PM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

lancaIV

                        tubi or not tubi ::)
          https://www.abacus-electronics.de/
                          Joachim Rieder

                     interestant,but not the target
          https://worldwide.espacenet.com/publicationDetails/biblio?FT=D&date=19860312&DB=EPODOC&locale=en_EP&CC=EP&NR=0173724A1&KC=A1&ND=5#
                        but here
https://worldwide.espacenet.com/publicationDetails/biblio?FT=D&date=19900104&DB=EPODOC&locale=en_EP&CC=DE&NR=3821856A1&KC=A1&ND=4#

It is known how a capacitor behaves on the network. Although this apparent current passes through, it does not consume any current. A capacitor absorbs current during the amplitude increase and supplies exactly this current during the amplitude drop back to the mains. However, if the capacitor is switched to the mains in the charged state during the amplitude drop, the charge is discharged into the mains, even if the charge does not originally originate from the network. When the mains voltage is zeroed, the capacitor must be disconnected from the mains again because otherwise it would be recharged from the mains with opposite polarity. Thus, when the capacitor is charged before any amplitude waste from any current source, and is discharged into the network during the amplitude drop, current is supplied to the network. If this capacitor makes this during the positive half-wave, a second capacitor can do this during the negative half-wave. The principle also works with only one half wave. In order to operate this principle, it is not necessary for the capacitor to be charged from the current source to the peak voltage, but any charge can be supplied with an arbitrarily lower voltage into the grid if either the residual charge is carried out up to the grid peak voltage or from the grid Capacitor is not connected to the mains until the mains voltage drops below the capacitor voltage. The capacitor is charged in the half wave break. The principle therefore supplies current to the network for as long as half the time of any number of periods. It actually produces the current consumed by phase-cut control, and it operates as a capacitive phase shifter. Both are very welcome in public networks. Due to the parallel operation, the primary energy carriers which are already present are used as memories and thus a further problem of regenerative energy forms is solved.  A practically constructed system uses triacs as switches, which are ignited by a mains frequency-controlled electronics.  The capacitors have no irrational size even at high power. Although these capacitors are operated only polarized, so-called MP capacitors should be used for safety reasons.  Two capacitors with 167 uF each provide a current of 10 amperes during the half-period at 50 Hz. This corresponds to a power of 1100 watts at 220 volts effective mains voltage when fully charged to the mains voltage. For this output power of a maximum of 20 watts is required. This principle also works effectively when considerably less regenerative energy is available in time.

     ex-urs-ion : jeah,Baerig gut

https://www.allaboutcircuits.com/textbook/alternating-current/chpt-11/true-reactive-and-apparent-power/

https://de.wikipedia.org/wiki/Anergie
            Anergie + Exergie = Energie

Magluvin

Quote from: Low-Q on September 16, 2017, 05:44:32 PM
The efficiency cannot be greater than the mechanical force x exursion of the actual speaker cone.
If you put two 112dB speakers in the same sealed enclosure, and power up one of them at resonance frequency, do you expect the same electrical energy output of the other speaker?


Even if you short circuit the second speaker, the powered speaker will still play. This proves that the speaker cannot have 100% efficiency.
You have 100% efficiency when the system (with one short circuit driver) is perfectly scilence no matter how many Watt you put in.


Vidar

I can understand that. But you are loading it differently and very badly to a point of stressing out the speaker as a whole and contorting the cone, inverting the rubber surrounds due to the pressures. That test would have to be the coil formers in direct physical connection with each other. Like if we had 2 of the 112db subs that are supposedly 100%eff this would test the drive motor of the speaker directly  If we took the pancake motor and put the armature in a vice to keep it from spinning, motor mounted to bench, then eff is 0%. Thats what I was saying earlier that its possible we need to look at how we load resonant circuits for the gain on output to be attained properly for best eff. Moving air, making sound waves through the air is the speakers load. It takes power to make the cone move back and forth at 1kw to rumble the window frames and nick nack on the mantle and metal garage doors in every house in the whole neighborhood. Do that with a 1kw fan, or power tool, what ever. The energy is realized at great distances in all directions. So we cannot say that moving air as a load is not a realistic load. Ask TK what he thinks of the amount of energy his home absorbs and rattles things from a distance when a guy booms down the street. Its real power.


Also, I had found in my resonant pendulum experiments where the pen had a magnet on the left side and one on the right, identical mags, and identical speaker coils for a driver and gen/pickup coil. I was able to get more voltage out of the gen coil than the supply was putting in the drive coil. Just that fact of more voltage should suggest something and we have seen many times if we put 2 identical dc motors shaft to shaft, the output voltage from the gen side will never ever reach the voltage of the drive motor and that is unloaded. And the other interesting thing I found with the pendulum experiments was that the positioning of the identical speaker coils to each magnet had to be a bit different in order to get the higher voltage out than in. What does that mean you may ask? Im in the belief that a dc motor that is specifically designed to be most eff at being a motor is not the best design for being a gen, and probably vice verse. I set the driver coil and pendulum to positions for max throw at given input, then bring in the gen coil for max voltage. Then I adjust both a bit at a time and I got more out than in on the voltage unloaded. Show me that you or anyone has accomplished that without using resonance and Ill quit the forum. lol. It cant be done without the resonance factored in. The positionings are not the same for each side. All using the identical mags and coils for the drive and the gen side.

Im dead set that me being able to get more voltage out on the gen side vs the input side at the freq of pendulum resonance is a big accomplishment. Nobody has shown that with an identical driver running a gen of the same magnets and coils, and they are operating at the same freq and speed of movement, not geared up in speed on the gen side. Im talking same as shaft to shaft identical motors. Now there may be a way to alter one of the motors to be a better gen, similar to me making the critical adjustments to the drive side and the gen side of the resonant pendulum experiments, but without resonance the altered motor to be a better gen still will not come close to the drive motor input voltage.


In the end, what Im hoping for is the possibility of 112db@1w may not be the upper limit. OU may be simpler than we think. Ill get into that later on. As in it might be possible that the speaker could be modified or redesigned to go above 112db@1w.   Like if the speaker really puts out 112db@1w, how do we account for resistance heat loss? Would the magnet/coil remain cool at continuous max rms power? If it is 100%eff comparing in and out, is it actually more eff than stated after we factor in the resistance heat losses, etc? Or is it the same as the cap discharge into an identical 0v empty cap where the resistance is not the reason for the 50%energy loss in doing so? ;) 112db@1w 100%eff in/out, plus free heat. lol

Lets see.

Mags




lancaIV

                            fluid dynamics
http://www.crystalinks.com/moving_sidewalks.html

http://www.crystalinks.com/vortex_in_vortex_out.gif
https://upload.wikimedia.org/wikipedia/commons/thumb/a/ae/World_line-de.svg/250px-World_line-de.svg.png

          https://en.wikipedia.org/wiki/Vortex_tube
this equation was published in 2012; it explains the fundamental operating principle of vortex tubes. The search for this explanation began in 1933 when the vortex tube was discovered and continued for more than 80 years.

forest

Quote from: lancaIV on September 16, 2017, 06:09:49 PM
(...)                     
It is known how a capacitor behaves on the network. Although this apparent current passes through, it does not consume any current. A capacitor absorbs current during the amplitude increase and supplies exactly this current during the amplitude drop back to the mains. However, if the capacitor is switched to the mains in the charged state during the amplitude drop, the charge is discharged into the mains, even if the charge does not originally originate from the network. When the mains voltage is zeroed, the capacitor must be disconnected from the mains again because otherwise it would be recharged from the mains with opposite polarity. Thus, when the capacitor is charged before any amplitude waste from any current source, and is discharged into the network during the amplitude drop, current is supplied to the network. If this capacitor makes this during the positive half-wave, a second capacitor can do this during the negative half-wave. The principle also works with only one half wave. In order to operate this principle, it is not necessary for the capacitor to be charged from the current source to the peak voltage, but any charge can be supplied with an arbitrarily lower voltage into the grid if either the residual charge is carried out up to the grid peak voltage or from the grid Capacitor is not connected to the mains until the mains voltage drops below the capacitor voltage. The capacitor is charged in the half wave break. The principle therefore supplies current to the network for as long as half the time of any number of periods. It actually produces the current consumed by phase-cut control, and it operates as a capacitive phase shifter. Both are very welcome in public networks. Due to the parallel operation, the primary energy carriers which are already present are used as memories and thus a further problem of regenerative energy forms is solved.  A practically constructed system uses triacs as switches, which are ignited by a mains frequency-controlled electronics.  The capacitors have no irrational size even at high power. Although these capacitors are operated only polarized, so-called MP capacitors should be used for safety reasons.  Two capacitors with 167 uF each provide a current of 10 amperes during the half-period at 50 Hz. This corresponds to a power of 1100 watts at 220 volts effective mains voltage when fully charged to the mains voltage. For this output power of a maximum of 20 watts is required. This principle also works effectively when considerably less regenerative energy is available in time.
(..)


This text is very interesting, is that a citation from patent ? Which one ?

lancaIV

                            Good morning,forest (PT-time ;) )

This one :                                        net-infeeder
https://worldwide.espacenet.com/publicationDetails/biblio?FT=D&date=19900104&DB=EPODOC&locale=en_EP&CC=DE&NR=3821856A1&KC=A1&ND=4#

and included "Citing documents" Applicant(s):  PETERS, HELMUT, 2854 LOXSTEDT, DE
https://worldwide.espacenet.com/publicationDetails/biblio?FT=D&date=19921015&DB=EPODOC&locale=en_EP&CC=DE&NR=9107538U1&KC=U1&ND=6#

The invention thus makes use of the fact that the inductor coil acts as a current store, which must first be "charged" when a voltage is applied, thus preventing a sudden rise in current, and that the current is subsequently passed through a choke coil by 90 ° of the alternating voltage applied thereto hurries.  According to the invention, the reactor coil is then switched as a buffer between the DC voltage network and the AC voltage network, whereby, in cooperation with the controllable switch, the surprising effect is obtained of being able to feed direct current directly into the AC voltage network without a short circuit between these two networks. This results in a considerably higher efficiency, in contrast to the known inverters, which results in a better energy yield. In addition, the waveform of the current fed into the alternating current network via the inductor coil is continuous and can be approximated to the ideal sinusoidal shape
better than the current generated by an inverter. 

https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=9&ND=3&adjacent=true&locale=en_EP&FT=D&date=19581014&CC=US&NR=2855860A&KC=A#
rexresearch : syphon Hydromat https://www.youtube.com/watch?v=Uhm22kxHhd8

                                                      https://www.youtube.com/watch?v=pFOXnp1pL_U
                                                    run forever: https://de.wikipedia.org/wiki/Ouroboros

to  electric amplifying syphon circuit :
https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=1&ND=3&adjacent=true&locale=en_EP&FT=D&date=19940318&CC=FR&NR=2695768A3&KC=A3#

Sonance and Resonance circuit system : https://worldwide.espacenet.com/publicationDetails/biblio?FT=D&date=19760504&DB=EPODOC&locale=en_EP&CC=US&NR=3955201A&KC=A&ND=4#