New gravity motor from China

[Dingus Mungus]

Hi Rob, hmm, I think you are right. That is a problem. The float displaces water out of the tube, when it goes in at the bottom and finally, when it exits at the top this much water then is missing inside the tube.... Hmm, can we find a way around it ?

Actually no... the three valve animation does take displacement in to account because of the negative pressure require to maintain the water level. I will further explain with some diagrams tonight when I'm done here at work.

Dingus you could be probably right.
It seems to require then every time to have at least 2 floats inside the tube at the
same time, right ?
And it also needs exactly your setup with the 3 shutting door plates,
right ?

Correct but it also requires resiviors with there own seals and timing...
I'm working on it now but having trouble with the timing right now.
I may have to work on it more tomorow...

too tired to think clearly tonight.

[Dingus Mungus]

I thought I had something but then I fully woke up...   

[FreeEnergy]

@FreeEnergy

unfortunately not.

Think about it.
When the float enters the tube from the bottom,
it displaces the same amount if water inside the tube, it
itsself has as its volume.
So after it has gone out of the top,
there is exactly this volume less water inside the tube..
Then this volume of water has to be pumped again into the tube,
but that needs again as much energy as was won,
when the float did rise to the top.
As the water is also heavier than the float,
indeed we need more energy to pump the water up
to the top.

The only trick I can think of is, to get the water up there
in a different fashion or only from a higher level, so you need
not to transport it from the lower level to the highest level
or don?t  use a hose to do it to overcome the hydrostatic pressure paradoxon...


Hmm, this is really a hard question to solve this puzzle...

this is why i said...
"ok add this to what the movie did not show...you know the open tank where the weight falls into???now picture that tank closed with a one-way(air proof) door where the weight falls into then AFTER it passes through the one-way door it falls into the water then goes up the pipe. when the weight reaches the top water will not desend because of the one-way door and the air sealed tank. you would also have a one-way door exit(air proof) at the top of the pipe."

the weight is in a vacuum before it hits the water then goes up the pipe.

[Dingus Mungus]

My original idea i thought would work appears to be inopperable without moving being able to move the weight from a high pressure zone to a low pressure zone with out the two zones reaching equalibrium. I am working on a new idea though and I feel it's a lot simpler then we are all thinking.

What if mechanicly they inserted an object with the same volume in to the water when the weight is removed and removed it from the water when a weight is dropped in to the water. 

That way the displaced water is always the same in both phases.

You should have heard the idea I woke up with last night... it was so bad it was embarassing.

[Dingus Mungus]

I have been working it out on a piece of paper and it appears to be totally feasible.
If others would like to work on the math, I'll be uploading a new visual design with
propper valve and displacement timing tonight after work.

Basicly its a two valve system with a accuating displacement weight.