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Overunity Machines Forum



MH's ideal coil and voltage question

Started by tinman, May 08, 2016, 04:42:41 AM

Previous topic - Next topic

0 Members and 22 Guests are viewing this topic.

Can a voltage exist across an ideal inductor that has a steady DC current flowing through it

yes it can
5 (25%)
no it cannot
11 (55%)
I have no idea
4 (20%)

Total Members Voted: 20

poynt99

Quote from: tinman on June 21, 2016, 12:43:10 AM
First up-thanks for taking the time for such an in depth  answer,but most of that i already know.
I am after a more in depth answer-what is the mechanism  behind the gradual buildup/ramp up of the current. I am thinking that it is the building of the magnetic field that is the root cause of the current building or ramping up over time. This magnetic field that changes over time,cuts the conducting windings,and we get our CEMF. This is what impedes on the current flow. As this magnetic fields change over time starts to slow in a linear fasion,we also see the current ramp up in the same linear fasion. The current reaches its  maximum  value when there is no change over time of the magnetic field.

Am i on the right track here?

Thanks


Brad
I would tend to agree that the sluggishness is caused by its own self-induction and cemf. Although I would say it is the electric field which induces the cemf, but in the end it makes no difference as to which perspective is used.

This page does a nice job of explaining it all.

QuoteThe reduction of current flow in a circuit due to induction is called inductive reactance. By taking a closer look at a coil of wire and applying Lenz's law, it can be seen how inductance reduces the flow of current in the circuit.
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

tinman

Quote from: MileHigh on June 21, 2016, 08:50:42 AM
There is no point in even trying to answer a question that has already been answered multiple times in multiple ways.  The expectation is the answer would just pass right through you like you weren't even there and chances are in two days you will post something that makes that readily apparent.

Lol-a side step MH ;)

I am well aware of self inductance in an inductor or coil MH,and what it means.
The question is to see that we are all on the same page here,although i am not really to worried if your reading the wrong book in this point in time.


Brad

tinman

Quote from: poynt99 on June 21, 2016, 09:06:13 AM
I would tend to agree that the sluggishness is caused by its own self-induction and cemf. Although I would say it is the electric field which induces the cemf, but in the end it makes no difference as to which perspective is used.

This page does a nice job of explaining it all.

Good,so we agree on that,and the electric field/magnetic field thing-well thats for another day,and im sure we can rig up a device to test that theory--one day.

But anyway,now we know that the CEMF is what reduces the rise time of the current flow from being instant-as in,as soon as we place a voltage across the inductor,the CEMF stop's the current rising to it's peak value instantly.

1-Would it there for be correct to say that--if there was no CEMF,the current would rise to it's peak value as soon as a voltage was placed across the inductor-or coil?.
2-What is the cause of the self induced EMF(CEMF) to be of a lesser value than the applied EMF?.


Brad

poynt99

Quote from: tinman on June 21, 2016, 09:24:20 AM
1-Would it there for be correct to say that--if there was no CEMF,the current would rise to it's peak value as soon as a voltage was placed across the inductor-or coil?.
I would agree.

Quote
2-What is the cause of the self induced EMF(CEMF) to be of a lesser value than the applied EMF?.
Good question. If you read that web page it tells you that the induced cemf is proportional to the number of turns in the coil. (you should read the link provided, it does explain everything).
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

MileHigh

Quote from: tinman on June 21, 2016, 09:24:20 AM
2-What is the cause of the self induced EMF(CEMF) to be of a lesser value than the applied EMF?.

Brad

And you are still stuck.  Surprise surprise.  The CEMF is identical to the applied EMF.  This was also covered in the thread multiple times.

Plus ça change, plus c'est la même chose.