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Overunity Machines Forum



MH's ideal coil and voltage question

Started by tinman, May 08, 2016, 04:42:41 AM

Previous topic - Next topic

0 Members and 13 Guests are viewing this topic.

Can a voltage exist across an ideal inductor that has a steady DC current flowing through it

yes it can
5 (25%)
no it cannot
11 (55%)
I have no idea
4 (20%)

Total Members Voted: 20

MileHigh

Quote from: tinman on June 24, 2016, 09:10:13 PM
Perhaps you could tell us all,as to why the current dose not shoot straight up to it's steady state value,when a voltage is place across it
What impedes on that current flow?

Brad

*CLICK*

You should not even be asking that question at this point in time.

hoptoad

Quote from: MileHigh on June 24, 2016, 09:06:16 PM
Yes, but there is no point in talking about the fact that there will be a very small resistance.  I already qualify that in my comments.  The first paragraph is not necessary.

To make things simpler, I already agreed that it makes sense to not call a voltage drop across a resistor CEMF.  I stated that at least TWICE.  So why are you and Brad stating that?   Why?

We do know how an ideal inductor will work.

Put simply, we do not 'know' how an ideal inductor will perform, we 'theorize' how it will/should perform and in practice attain good approximations of the theory.

tinman

 author=MileHigh link=topic=16589.msg487098#msg487098 date=1466818180]


QuoteThat's a real doozie Brad.  Let's see, I probably first learned about a time constant in 1977.  Do you really think I don't know what the approximate values are?  I was tired and just threw up some arbitrary numbers for illustrative purposes.

What a whole lot of crap MH.
You threw those numbers up to make my explanation look wrong,but it is right,and you are a lyre.

QuoteSo here you are making a complete fool of yourself, a spectacle of yourself, by "pretending" that I don't know the approximate value of the first time constant.  That's you cynically being an asshole for all to see.

What it shows MH,is how deceitful you can be,in trying to make some one else look wrong.
But once again,i caught you out in your pathetic attempt at doing so.

QuoteYou are such a little imp, I think you need a good spanking.
Bad little imp boy!  You read multiple times how I agreed that it is more appropriate to avoid that term for a resistor.  Little imp boy needs another spanking, count down from 200.
Now count down from 300.
Now count down from 400.  That's what you call beet red for being a bad boy.

Your pathetic.
You are also no where big enough to give me any sort of spanking--you never have,and never will.

QuoteNo it doesn't create a current flow in the OPPOSITE direction.  That is a nonsensical idiotic fantasy that does not happen and you will never find a single stitch of evidence for that.  It's a bad-old-days belligerent Brad fantasy.

Wrong again,as i can show it on my bench--no problem at all.
What you dont get,is that the reverse current flow is subtracted from the induced current flow,and you cannot separate the two,as one subtracts from the other,and all you see is the end resulting value.

QuoteThe EMF source is say a battery, and the CEMF source from the coil looks like another battery.  That's two EMF sources facing each other at the same potential and so NO CURRENT FLOWS towards the battery driving the coil.

And there you go--you just shot your self in the foot again.
You said that the CEMF is always equal and opposite to the EMF,but current will still flow.
Now you have just shown us all that if the CEMF and EMF are the same value,no current will flow lol ;--Good one MH  ;)

QuoteYou have about as much electronics common sense as lumpy gravy.  Your whackadoo fantasy story is completely and utterly ridiculous and after all the work that was done in this thread you should be embarrassed for regressing once again.  Like I have told you, GET SOME ELECTRONICS BOOKS AND LOCK YOURSELF IN A ROOM FOR A MONTH AND READ THEM AND UNDERSTAND THEM.

My lumpy gravy MH,is the same lumpy gravy that PW,Poynt,Hoptoad,and everyone else here are eating.
Sorry cobba--you have been outvoted on this one.

QuoteAnybody can read this thread from the beginning through the end with a doorman's clicker, the type used to count the number of people in the club.  Every time you have "a moment" the person can register a click.  Seriously, you wouldn't want to know what the count was when they got to this very posting.

I think you had better take a walk back in time MH,and see who has the most clicks against there name-->you win hands down.
We have had all sorts of wackadoo from you in this thread,and the JT thread--the latest being your attempt to discredit what i said about the CEMF current value being the difference between that of the peak current at each time constant,and the steady state current.
I was correct,and you were of in wackadoo land.

Here is what i said--It you take the peak current value that will be flowing at the 5th time constant,and you subtract from that the peak current value of the first time constant,you are left with the calculated reverse current produced by the CEMF.

Here is your attempt to discredit my claim
Quote: So like if the 5th time constant current is 100 amps and the 1st time constant current is 25 amps then the reverse current produced by the CEMF is 75 amps.   So does that mean when you first apply the voltage across the coil the current is -75 amps?  It's "Attack from Planet Bizarro and the Pumpkin Patch Creatures."

As you can see,an idiotic attempt to discredit what i said,and the only bizarro comes from you.
You know dam well that if you had of used the correct values for each time constant,what i stated is absolutely true. But no,you had to pluck some incorrect numbers out of your wackadoo head,so as to try and make others believe that i dont know what im talking about--your pathetic.
The correct amounts using your 100 amp steady state current flow.
At the end of the first time constant,the current flowing through the coil will be 63.2 amp's,and the reverse current value from the self induced EMF will be 36.8 amps.
Perhaps PW,Poynt or Hoptoad would like to confirm what i said.

MH-face it--you got caught out again at trying to discredit me,and you had another epic fail-as you do often-->the latest being your CEMF producing resistor.
I was the first to tell you that is crap,and you gave me a mouthful,and said i had no idea what i was talking about. But then Poynt,PW,and Hoptoad had to slap some sense into you,and now you have admitted it was another stupid thing to say.


Keep going MH,your hole is getting deeper by the day.


Brad

tinman

Quote from: MileHigh on June 24, 2016, 09:32:21 PM
*CLICK*

You should not even be asking that question at this point in time.

Well not from you anyway.

Im fine with the question MH,but it seems you have a little trouble with it.
Im sure all the info you need to catch up,is out there for you to find.


Brad

MileHigh

This is one of those times when it feels like it is completely and utterly hopeless with you Brad.

QuoteAnd there you go--you just shot your self in the foot again.
You said that the CEMF is always equal and opposite to the EMF,but current will still flow.
Now you have just shown us all that if the CEMF and EMF are the same value,no current will flow lol ;--Good one MH 

*CLICK*

No current will flow into the battery due to the CEMF from the coil.

Current will flow due to the battery's EMF being imposed on the coil due to the nature of the coil.

But you are such an electronics simpleton sometimes that some basic critical thinking skills like looking at the situation from both perspectives is beyond your thinking capability.  It's just hopeless.