My Theory! I can't find why it wouldn't work! Big suprize!

[nwman]

Doesn't work sorry!

[MeggerMan]

Hi Nwman,
OK the way I explained it is not very scientific, my physics lecturer from my college days would probably cringe at my poor explanation.

Lets try it again:

A-----O-----B

A = 1Kg
B = 1Kg
A to 0 = 5m
B to 0 = 5m

force = mass x acceleration
acceleration or g = 9.8 but for to simpify we can use 10.

Moments of A = mass x acceleration x distance = 1 x 10 x 5 = 50nm
Moments of B = mass x acceleration x distance = 1 x 10 x 5 = 50nm


If you move B 1m to the right it now becomes:
Moments of B = 1 x 10 x 6 = 60nm

Difference = moments of A - moments of B = 50 - 60 = 10 nm
To work out the stored energy at this position you need to work the effective mass which is
(force x g) / distance = (10 x 10)/6 = 0.1666 Kg

The energy is force x distance = 0.16666 * 10 * 6 = 10 joules
OK you could work out the rotation energy by doing lots of small increments of a rotation and work out each small piece of energy, but it should come out as 10 joules.

Now to raise the weight B back up the 1m will require some work: mass x acceleration x distance = 1 x 10 x 1 = 10 joules.

Increasing the number of spokes makes no difference.

Regards

Rob

[nwman]

Doesn't work sorry!

[nwman]

Doesn't work sorry!

[Dingus Mungus]

Now you just have to find a way to lift the weights...