TD replications

[lumen]

Though... I'm not saying the cam is a bad idea, in fact it adds an interesting effect in that it can leverage the higher forces when it's needed and yet during extraction at mid rotation where there is zero force, there is no effect.

I hope to be getting back to do a bit more testing myself.

Keep on it maybe something will come of all this.

[gotoluc]

Though... I'm not saying the cam is a bad idea, in fact it adds an interesting effect in that it can leverage the higher forces when it's needed and yet during extraction at mid rotation where there is zero force, there is no effect.

I hope to be getting back to do a bit more testing myself.

Keep on it maybe something will come of all this.

Thanks for clearing up what you had in mind when you wrote your post.
We'll see how it will turn out.
I would rather build another test device rather then modifying the first one to further test other possibilities. So if for some reason the 2nd device gets worse, I can always go back to the first one to try to understand what makes the difference.


Yes, I do hope something comes of it.


Luc

[gotoluc]

Hi floor and everyone,


My research continues even though I haven't posted for a few weeks!


I've made an update video for all to see the tests I'm doing before the full rotary version build so I know which magnet geometry I'll be using.


Link to video: https://www.youtube.com/watch?v=qQjp1ysvlOQ


Luc

[TinselKoala]

QUOTE from DrJones
"So the work = mechanical energy = Torque x Theta, not just Torque alone.
I'm concerned that Theta has been left out in the analysis so far in this thread -
and hope that Theta will be included in the future. "END QUOTE

Two questions

1. The conversion of torque to work is needed,
          in order
to state the actions in terms of Joules of work. Correct ? 

2. But  that conversion to joules, will not change the RATIOS
of the measurements to each other, will it ?

                        thanks for being on board
                                   floor

Nice work Luc. I haven't really been following along closely but I just wanted to throw this in:

Let me underscore this point, and put it another way:

Luc's data seem to be showing that t2 (output torque) is greater than t1 (input torque). But torque isn't energy or work, even though they have the same units. Torque is a vector whereas energy is a scalar, and torque is the rotational analog of force. The energy (or work) in Joules associated with a torque is given by E = (torque x angular displacement), where torque is in Newton-meters and angular displacement is in radians. So a torque of 1 N-m applied for a full rotation requires an energy (work) of 2pi Joules.

So to answer Floor's question, yes, it is possible to have t2 > t1 but still have E2 <= E1 if the torque t2 acts over a smaller angle than t1.

I can't tell from Luc's data whether you are taking this into account.

[gotoluc]

Thanks TK,

I'm glad you're looking into this.
Unfortunately (as you may know) I have no schooling, so we have a certain communication incompatibility when technical terms are used. However, I'll do what I can to provide any details you may need but keep in mind (when dealing with me) best to use plain words, no math equations or symbols.

I do appreciate your input and hopefully floor can answer your question.

Kind regards

Luc