re: energy producing experiments

[Low-Q]

https://youtu.be/YaUmzekdxTQ

This experiment produces energy

Any given effect has a bad tendency to be a result of the cause. In other words, it is very hard, if not impossible, to achieve an effect that does not have any connection to the cause. If it wasn't your calculator would be useless. 1-1=0 no matter how hard you try to change the result.
The cause is your hand, the effect is two balls having fun around a PVC tube. The mechanical movement is a direct cause of the energy you supply by your hand.

[Delburt Phend]

When a force causes a mass to move in a particular direction that is the positive direction for that mass. It does not matter what the actual direction is (N, S, E, W, up, down, left, right). When the same force causes a different mass to move in a different direction that direction is still the positive direct for that mass. And the momentums of the two masses are added.
 
Proof: An Atwood's machine is used to prove F = ma. A little over half of the motion in an Atwood's is going down and a little less than halve is going up; but the two momentums are added.
 
So you are not going to make vector mistakes again are you. When one force causes different masses to move in different directions all the directions are positive and the momentums are added together.
 
A 97.63 kilogram Atwood's with 25 extra kilograms (122.63 total mass) on one side will accelerate to 2 meter per second velocity after the 25 kilograms has dropped 1 meter. This drop will take one second. With 9.81 newtons per kilogram for 25 kilograms applied for one second; this is 245.25 newton seconds.
 
After this Atwood's is in motion it can apply 245.25 newtons for one second.
 
When 9.81 newtons is applied to this Atwood's it will take 25 seconds to make the Atwood's stop.
 
When 9.81 newtons is applied to a one kilogram mass for 25 seconds it will be moving 245.25 m/sec.
 
A one kilogram mass moving 245.25 m/sec will rise for 25 second. And it will rise 3065.625 meters.
 
This is 3065.625 m * 9.81 newtons/ kg * 1 kg = 30,073.78 joules of energy.
 
Twenty five kilograms dropped one meter is 25 kg  * 9.81 N/kg * 1 m = 245.25 joules
 
So with 245.25 joule you can make 30,073.78 joules.

[Delburt Phend]

https://www.youtube.com/watch?v=aa-YoJjIPAo

[sm0ky2]

https://www.youtube.com/watch?v=aa-YoJjIPAo

Excellent!


Now comes the important part


E = (m2-m1)gh
Where h is the distance downward the large mass moves
during the experiment.


You see that energy is conserved

[Delburt Phend]

That is correct: the total mass of the Atwood's in the video is 40 kg and the accelerating mass is 20 kilograms. The 20 kg in the balanced portion of the Atwood's is not dropped; only the extra 20 kg is lowered.
 
Twenty kilograms at a height of one meter has a potential energy of (1 m * 20 kg * 9.81 N/kg) 196.2 joules.
 
Twenty kilograms dropped one meter in free fall has a velocity of 4.429 m/sec for an energy of (1/2 * 20 kg * 4.429 m/sec * 4.429 m/sec) = 196.2 joules.
 
The 20 kg /40 kg Atwood's has a final velocity of 3.132 m/sec after the 20 kg drops 1 m; this is (1/2 * 40 kg * 3.132²) = 196.2 joules.
 
A twenty meter long string that has one kilogram at each one meter length has 196.2 joules of energy after it is dropped one meter.
 
A twenty meter long string that has one kilogram at each one meter length has 196.2 joules of potential energy when it is raised one meter.
 
A one kilogram mass dropped 20 meters has a final velocity of 19.81 m/sec for 196.2 joules of energy.
 
So: 196.2 joules for everything; so far.
 
The 20 kg /40 kg Atwood's has a final velocity of 3.132 m/sec after a drop of 1 m; this is (40 kg *3.132 m/sec) = 125.28 units of momentum.
 
As proven by the double stopping cylinder and spheres you can place all of that momentum into one kilogram.
 
For one kilogram to have 125.28 units of momentum it must be moving 125.28 m/sec.
 
One kilogram moving 125.28 m/sec will rise (1/2 *125.28² / 9.81 m/sec) = 800 meters.
 
The potential energy of 1 kg at a height of 800 meters is (800 m * 9.81 N/kg * 1 kg) = 7848 joules of energy.
 
A 7848 J / 196.2 J = 4000% increase over the original energy.
 
Please note that there is no mention of radius.  Which eliminates what?
 
It is also important to note that all the 196.2 joules listed are from an original production of motion; they are not transfers of previously existing motion.
 
If the one kilogram moving 19.81 m/sec were to transfer its motion to the Atwood's at rest it would only be moving .48317 m/sec for only 4.786 joules of energy not 196.2 J. 
 
If the 20 kg moving 4.429 m/sec were to join its motion to the Atwood's at rest it would have (20 * 4.429 = 60 * X) = 1.4765 m/sec for 59.1 joules of energy not 196.2.
 
Momentum is always conserved in the transfer of motion from one objects to another not energy. And radius is never mentioned; so what kind of momentum is it?