The bifilar pancake coil at its resonant frequency

[synchro1]

@Tinselkoala,


Times up! The spark discharge is at the speed of light, and the graph line is on the perpendicular. Your turn to admit your wrong!

[Magluvin]

@Mags,


I don't want to compound the problem too much. I explained that my intention was to imply that the curves are non chiral and symmetrical. I also explained that there's an RC formula for the time that involves a resistor. Now, I don't want to be accused of trying to weasel out of a pickle, but if the capacitor is discharged through a high value resistor, wouldn't it take some additional time for the resistor to begin to pass the current? It would depend on which side of the resistor you measured the discharge from right?

If the resistor were absent of induction, the discharge from the cap through the resistor would begin delivering max current instantly, max current determined by V/R. The resistance determines the time of complete discharge, more resistance, longer time to 0V. If we shrink from left to right the time chart of the discharge through a very high resistance compared to the short time it would take through a very low resistance, the curve should look the same, with the bulk of the charge diminished more quickly closer to the beginning of the discharge and the rate of discharge gets smaller the closer the cap reaches 0v.

If there is some sort of delay, what is causing the delay you express?

Mags

[synchro1]

If the resistor were absent of induction, the discharge from the cap through the resistor would begin delivering max current instantly, max current determined by V/R. The resistance determines the time of complete discharge, more resistance, longer time to 0V. If we shrink from left to right the time chart of the discharge through a very high resistance compared to the short time it would take through a very low resistance, the curve should look the same, with the bulk of the charge diminished more quickly closer to the beginning of the discharge and the rate of discharge gets smaller the closer the cap reaches 0v.

If there is some sort of delay, what is causing the delay you express?

Mags

@Mags,

Eddy hysteresis. Worse in the bottle neck! I'm talking about the water flow through the bottle neck there, not the capacitor discharge. All comparisons are not exactly the same as the real thing.

[TinselKoala]

@Tinselkoala,


The maximum discharge is between 100% and 63% of the charge, the maximum charge level is between 0% and 37%, then it begins too slow down to 63% where the time frame elongates again to match the 37% level of the discharge. Everyone knows it takes longer to charge a capacitor after it's 63% full then at the beginning and conversely, it takes longer to discharge the remaining 37% as it empties out. We have an inverse but symmetrical curve. Got it?

Still trying to weasel out of your pickle, I see. What does the word "RATE" mean to you? How about "ASYMPTOTE"?

Clearly, the maximum charge "LEVEL" is also right at the beginning of the discharge, and the minimum charge "LEVEL" is at the very end.

GOT IT?

Yes, you have inverse and symmetrical curves. And these curves clearly show that the maximum charge RATE and the minimum charge LEVEL occur at the beginning of the charge, and the maximum discharge RATE and the maximum charge LEVEL occur at the beginning of the discharge. Not at the 33 or 67 percent charge levels.

But need I remind you once again what you actually said in your original claim?

[TinselKoala]

@Tinselkoala,


Times up! The spark discharge is at the speed of light, and the graph line is on the perpendicular. Your turn to admit your wrong!

Nope. The spark discharge is not "zero resistance" nor is it at the speed of light, the speed of light is not infinite, and a perpendicular or rather vertical line on any quantity-time graph means that the quantity changes _instantly_, that is with zero time passing. And this does not occur in any real system, especially not capacitor discharge.

And it's "you're" not "your", as in "You're wrong yet again synchro."