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3.7 VOLT BATTERY POWERS 56 WATTS

Started by magnetman12003, March 28, 2017, 07:46:43 PM

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magnetman12003

Quote from: TinselKoala on March 28, 2017, 10:52:00 PM
1. Power is not energy.
2. A nameplate or box value does not mean that the bulb or other device always draws that amount of power.
3. "Undimmable" does not mean that the bulbs cannot shine at reduced brightness.
4. Visual impressions of brightness are nearly worthless as "measurements".
5. Power is not energy, and it is entirely possible for a battery like yours to deliver hundreds of watts or even more. Try shorting the terminals with a piece of wire and see what happens.

Carry on, keep experimenting, study and learn.
I did short the wires while experimenting and after a very loud stinking crack I found I had
blown up my new wattmeter..  The circuit however still is working.  LOTS OF CURRENT!

gyulasun

Quote from: magnetman12003 on March 29, 2017, 02:04:44 PM
My circuit is self looped  The negative input is connected DIRECTLY to the negative output.

Hi Thomas,

Just because of the negative input is connected to the negative output, your circuit is not self looped. This is not enough condition for self looping.
I assume your setup creates around 12V DC output that feeds directly the 8 LED lamps, right?

What is needed for self looping in your case is to use an efficient DC-DC step down converter, see what I mean:
http://www.ebay.com/itm/222366957908    there are many types, this is cheap and free shipping and yet seems suitable.

Such converter receives any DC input between 4.5V and 24V and has a potmeter-adjustable output voltage range between 0.18V and 17V and output current max 3A. The negative input is internally connected to the negative output as is the case for any non-isolated type converters.

So you could feed your 12 V output from your setup to the input of such DC-DC converter and the output of this converter would be connected to the 5V input of your setup via a series diode placed in the positive output of the step down converter.
And when you have connected like this, you could completely remove the 5 V phone charger that presently includes the 3.7V battery and see whether your setup continues feeding the lamps or bogs down.
This would be a correct and true self looping and you could experience first hand whether your setup is really able to maintain operation and feed the lamps under a looped back condition.

Before doing the self loop, you may wish to remove say 7 LED lamps out of the 8, this low-load condition would make it easier for your setup to "focus on" feeding the load coming from the step down converter the moment you close the loop.

I made a block diagram for you to show a possible looped wiring for the whole setup. Red lines are the positive rails and blacks are the common negative ones.  Diode D is needed to separate the 5V output of the phone charger from the 5V output of the step down converter to avoid mutual loading of the 5V outputs. When you have done the looping and removed the phone charger and the setup continues feeding the lamps, the D diode is not needed any more, it is a temporary component while the 5V output of the phone charger is present.
You need to adjust the output voltage of the step down converter in advance to roughly 5.6V when you feed its input from a 12V wall plug adapter. Diode should be able to handle 3 Amper at least, here is a suggestion:  http://www.futurlec.com/Diodes/1N5401pr.shtml 

If you have questions, please ask.  If you do the looping, please report back what you experienced.

Gyula

SkyWatcher123

Hi all, hi magnetman, will you share the circuit for this please.
peace love light

magnetman12003

I have the same setup being powered by a 12 volt wall wart.  To keep voltage constant.
Here it is:
https://www.youtube.com/watch?v=o30z1iHDZa8


SkyWatcher123

Hi magnetman, thanks for sharing, though will you share the circuit drawing and details.
I mean, if you will share them freely to a corporation, etc. then why not share them here, so people can benefit from your device.
peace love light