Dr Ronald Stiffler SEC technology

[erfandl]

Hi Erfandl,
Thanks for the Lux meter screenshots, they nicely show the higher light outputs as you placed 2 and 3 crystals in parallel.

Okay on your boost converter has 24 V DC output, and its input receives the 3.7 V battery.
Now please explain where is the 3.4 mA current measured you mentioned in your earlier post above? Or was it 34 mA?

I understand that the current input to the oscillator reduces when you use 3 crystals (from 28.4 mA to 23.1 mA):  did you use the 24 V DC from the boost converter back then?

Thanks,
Gyula

sorry for the battery current. the battery current today I testing is 228 mAh. now I using 5 crystal, output current is 20 mAh and brightness output is 10150 LUX.

[gyulasun]

Why not try crystals of _different_ frequencies in the parallel stack? The spectrum analyzer display should be interesting....

Yes, this would be a good next step in exploring this.  I think the oscillator will become and function
as an RF mixer too. 
Provided the second crystal is willing to oscillate too, in parallel with the 13.56 MHz,   that is...   
You may happen to have crystals with say a few MHz less frequency than 13.56 MHz.
And for a start, just use a single 13.56 MHz and another single crystal only, say with having a lower frequency.
Gyula

[gyulasun]

sorry for the battery current. the battery current today I testing is 228 mAh. now I using 5 crystal, output current
is 20 mAh and brightness output is 10150 LUX.

Dear Erfandl,
Sorry for nagging you with these current values,  I thought if you report results, then the data should be written correctly
what your meters really show, this is all, no offense intended. 

Thanks for these new current values.  Would like to ask that the 20 mA current you mention now is taken from
your booster converter, right? 

Was the converter output voltage set to 24 V ?
And please do not use mAh for current it should be mA only.   mAh is for good for battery capacity.   

Thanks for all your kind efforts.
Gyula

[erfandl]

Dear Erfandl,
Sorry for nagging you with these current values,  I thought if you report results, then the data should be written correctly
what your meters really show, this is all, no offense intended. 

Thanks for these new current values.  Would like to ask that the 20 mA current you mention now is taken fromyour booster converter, right? 
Was the converter output voltage set to 24 V ?
And please do not use mAh for current it should be mA only.   mAh is for good for battery capacity.   

Thanks for all your kind efforts.
Gyula

Yes. The current output from boost converter is 20 mA and boost converter output voltage is 24 volt.
Your welcome Gyula :X

[gyulasun]

Okay Erfandl, thanks. 

Notice:  if the current taken from the 3.7 V battery is 228 mA, then power used is 843 mW.             

             Power taken from the converter output is 24 V x 20 mA= 480 mW  Compare the two...